Assuming you want the equation in slope intercept form, you first need to use slope formula to find the slope.

Plug in the coordinates that you have, (3,-1) and (4,7), for the x and y values respectively.

Which reduces to 8/1=8.
The slope of your equation is 8.
Slope intercept form is: y=mx+b. m is your slope and b is your y-intercept, x and y stay unchanged.
Plug the slope in:
y=8x+b.
Now, you can plug one of the sets of coordinates into the x and y of the equation to find b. I'm using (3,-1).
-1=8(3)+b
-1=24+b
Subtract 24 from both sides.
-25=b
Now plug this into the equation!
y=8x-25 is your final equation.
I hope this helps :)
Answer:
200 inches of ribbon
Step-by-step explanation:
if the formula to finding an area is s²
and we already know that the area is 400, so we divide the area by 1/2 to get the length of each side
Answer:
6.31 mi
Step-by-step explanation:
The diagram below explains the solution better.
From the diagram,
C = starting point of the race.
A = end of the first part of the race.
B = end of the race.
Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.
Cosine rule states that:
![a^2 = b^2 + c^2 - 2bc[cos(A)]](https://tex.z-dn.net/?f=a%5E2%20%3D%20b%5E2%20%2B%20c%5E2%20-%202bc%5Bcos%28A%29%5D)
where A = angle A = <A
Given that
b = 5.2 miles
c = 2.0 miles
<A = 115° (from the diagram)
Hence,
![a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi](https://tex.z-dn.net/?f=a%5E2%20%3D%205.2%5E2%20%2B%202.0%5E2%20-%202%2A5.2%2A2.0%5Bcos%28115%29%5D%5C%5C%5C%5Ca%5E2%20%3D%2027.04%20%2B%204%20-%2020.8%5Bcos%28115%29%5D%5C%5C%5C%5Ca%5E2%20%3D%2031.04%20%2B%208.79%5C%5C%5C%5Ca%5E2%20%3D%2039.83%5C%5C%5C%5Ca%20%3D%20%5Csqrt%7B39.83%7D%5C%5C%20%5C%5Ca%20%3D%206.31%20mi)
The straight-line distance between the starting point and the end of the race is 6.31 mi
126 divided by 7 equals 18
18 m