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Alik [6]
4 years ago
14

Determine whether the study depicts an observational study or an experiment. Thirty university students are divided into two gro

ups. One group receives free tutoring in mathematics comma the other doesn't. After one semester comma scores on final mathematical examinations are compared.
Mathematics
1 answer:
alex41 [277]4 years ago
6 0

Answer:

The provided study is an experiment.

Step-by-step explanation:

Consider the provided information.

Observational study: In this study observer only observe the subjects, and measure variables of interest without allocating treatments to subjects.

For example: you want to examine the  side effect of smoke on lung.

Experiment study:The researchers are applying treatments to experimental units in the research, then the effect of the treatments on the experimental units is observed.

For example: Flipping a coin

Now consider the provided information:

Thirty university students are divided into two groups. One group receives free tutoring in mathematics comma the other doesn't. After one semester comma scores on final mathematical examinations are compared.

Here, the researcher applying treatment to experimental units.

Thus, the provided study is an experiment.

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(PLEASE HELP) A local newspaper charges g dollars for a four-line classified ad. Each additional line costs d dollars. Write an
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Answer:

g + 3d

Step-by-step explanation:

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4 0
2 years ago
Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1
nikklg [1K]
Given

\Sigma_{n=1}^\infty15(-4)^n

The first 10 partial sums are as follows:

S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\  \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\  \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\  \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\  \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}

S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}

The rest of the partial sums can be obtained in similar way.
7 0
3 years ago
Pls help me. its on khan academy​
ehidna [41]
i would think it’s 6
8 0
3 years ago
Read 2 more answers
BRAINLEST again PLZ HELP
Vlad1618 [11]
Is that all that the question says ?
5 0
3 years ago
Round 3,058 to the nearest thousand
daser333 [38]
3,058 round to the the Thousands place is 3,000
Hope this helps!
7 0
3 years ago
Read 2 more answers
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