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Anon25 [30]
3 years ago
9

What is the measure of arc BD shown in the diagram below?

Mathematics
2 answers:
morpeh [17]3 years ago
7 0
We know that
<span>The measure of the external angle is the semi-difference of the arcs that it covers.
</span>so
m∠BCD=(1/2)*[arc AE-arc BD]
20=(1/2)*[85-BD]
40=85-BD
BD=85-40
BD=45°

the answer is
BD=45°
kicyunya [14]3 years ago
7 0

the the measure of arc BD is : 45°

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Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
sdas [7]

Answer:

-15

Step-by-step explanation:

We proceed as follows;

In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.

Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.

Thus, we have;

2a(b-3) + 5b + _

Now, putting -15 will give us the same expression in the first bracket and this gives us the following;

2a(b-3) + 5b-15

2a(b-3) + 5(b-3)

So we can have ; (2a+5)(b-3)

Hence the constant used is -15

8 0
4 years ago
1 1/3 miles in 1/4 hours
Romashka [77]

Answer:

So even though it'll be a little strange, you do just take the miles and divide by the hours.  Since 1 1/3 is the same as 4/3 then the rate = (4/3)/(1/4).  

That's the same as 4/3 * 4 = 16/3 miles per hour.  Or 5 1/3 miles per hour.

Step-by-step explanation:

6 0
3 years ago
Solve. z – 9 = 27 a. 3 b. 16 c. 18 d. 36
Rashid [163]
z - 9 = 27 

z - 9 = 27:z 

z=27+9  | Combine \ like \ terms|  |Add \ 9 \ to \ both \ sides| 

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8 0
4 years ago
Read 2 more answers
A kite is designed on a rectangular grid with squares that measure 1cm by 1 cm. A hexagonal piece within the kite will be reserv
Nata [24]

Answer:

The answer is the first answer

P = 8 + 4√13 cm

A = 36 cm²

Step-by-step explanation:

* Lets study the figure

- Its a kite with two diagonals

- The shortest one is 12 cm

- The longest one is 26 ⇒ axis of symmetry of the kite

- the shortest diagonal divides the longest into two parts

- The smallest part is 8 cm and the largest one is 18 cm

* To find the area reserved for the logo divide

 the hexagonal piece into two congruent trapezium

- The length of the two parallel bases are 4 cm and 8 cm and

  its height is 3 cm

- The length of non-parallel bases can calculated by Pythagoras rule

∵ The lengths of the two perpendicular sides are 2 cm and 3 cm

- 3 cm is the height of the trapezium

- 2 cm its the difference between the 2 parallel bases ÷ 2

  (8 - 4)/2 = 4/2 = 2 cm

∴ The length of the non-parallel base = √(2² + 3²) = √13

* Now we can find the area of the space reserved for the logo

- The area of the trapezium = (1/2)(b1 + b2) × h

∴ The area = (1/2)(4 + 8) × 3 = (1/2)(12)(3) = 18 cm²

∵ The space reserved for the logo are 2 trapezium

∴ The area reserved for the logo = 2 × 18 = 36 cm²

* The area of the reserved space for the logo = 36 cm²

* The perimeter of the reserved space for the logo is the

  perimeter of the hexagon

∵ The lengths of the sides of the hexagon are:

   4 cm , 4 cm , √13 cm , √13 cm , √13 cm , √13 cm

∴ The perimeter = 2(4) + 4(√13) = 8 + 4√13 cm

* The perimeter of the reserved space for the logo = 8 + 4√13 cm

4 0
3 years ago
Someone please help me quickly i will give brainlyist
scZoUnD [109]

(16,5) it should be

16 input

5 output

if you went to 5 ont he y-axis and keep going till it hits the line the x seems to be 16.

im deeply sorry if this is wrong.

4 0
3 years ago
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