What is the measure of arc BD shown in the diagram below?

Mathematics

2 answers:

morpeh [17]3 years ago

7 0

We know that
<span>The measure of the external angle is the semi-difference of the arcs that it covers.
</span>so
m∠BCD=(1/2)*[arc AE-arc BD]
20=(1/2)*[85-BD]
40=85-BD
BD=85-40
BD=45°

the answer is
BD=45°

kicyunya [14]3 years ago

7 0

the the measure of arc BD is : 45°

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