Hypothesis (p): A polygon is a square
Conclusion: (q): It is a rectangle
Inverse: q → p <em>If a polygon is a rectangle, then it is a square</em>
Converse: ~p → ~q <em>If a polygon is not a square, then it is not a rectangle.</em>
Contrapositive: ~q → ~p <em>If a polygon is not a rectangle, then it is not a square</em>
Your answers are correct
So hmmm notice the picture below
thus

solve for "h"
Answer:
x ≤ 3
Step-by-step explanation:
2(4+2x) ≥ 5x+5 (by PEDMAS, expand parentheses first)
4(2) + 2x(2) ≥ 5x + 5
8 + 4x ≥ 5x + 5 (subtract 8 from each side)
4x ≥ 5x + 5 - 8
4x ≥ 5x - 3 (subtract 5x from both sides)
4x -5x ≥ - 3
-x ≥ - 3 (multiply both sides by -1, remember to flip the inequality when multiplying both sides by a negative number)
x ≤ 3
Answer:
<h3>I THINK ITS • (4X2+32X+64-π(x2+2x+1))</h3>
Step-by-step explanation:
i hope it helps :)