Represent even numbers as "2n" since each is a multiple of 2.
Represent odd numbers as "2n+1" since each is one more than an even.
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Your problem:
smaller # : 2n
larger #: 2n+2
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EQUATION:
2n+2 + 3(2n) = 234
8n = 232
n = 29
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smaller = 2*29 = 58
larger = 2n+2 = 60
Answer:
ok
Step-by-step explanation:
Answer:
1. C. Yes, because a sum of cubes can be factored
2a. false
2b. false
2c. true
2d. false (based on what is written in the equation; refer to step-by-step)
Step-by-step explanation:
1. Both 3 and 8 can be cubed, which is why x^3+8 can be factored (x+2)(x^2-2x+4)
2a. a^2-b^2 can be factored by the perfect square rule, so it should be (a-b)^2
2b. both terms are perfect squares, so you can factor, making it (a+b)(a-b)
2c. You can factor using the perfect square rule, making it (a+b)^2
2d. Most of what is in the equation is true, yet the correct solution would be (a-b)(a^2+ab+b^2)
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