Question

Lim as x approaches 5 from the right (x-5)/(x^2-25)

Answer 1

$\lim_{x \to 5^+} \frac{x-5}{x^2-25} = \lim_{x \to 5^+} \frac{x-5}{(x-5)(x+5)} = \lim_{x \to 5^+} \frac{1}{x+5} = \infty$