Does this graph represent a function?

Mathematics

1 answer:

just olya [345]3 years ago

5 0

Yea it does! it goes up

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HELP!!THANKS FOR ACCURACY

anyanavicka [17]

$\bf tan^2(x)-1=0\implies tan^2(x)=1\implies tan(x)=\pm\sqrt{1} \\\\\\ tan^{-1}[tan(x)]=tan^{-1}(\pm 1)\implies x=tan^{-1}(\pm 1)\implies x= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4}\\\\ \frac{5\pi }{4}\\\\ \frac{7\pi }{4} \end{cases}$

5 0

3 years ago

(5x-6) + (2x-6)add the polynomials

Thepotemich [5.8K]

In this question, let's add those polynomials

(5x-6) + (2x-6)

5x -6 +2x -6 Combine like terms

5x +2x -6-6

7x -12

Since this is not an equation, no further step can be done.

8 0

1 year ago

Pls guys help me pls :c

Vinil7 [7]

Answer: A. $x\geq21\dfrac{2}{3}$ .

Step-by-step explanation:

The given inequation: $81-1\dfrac{1}{5}x\leq55$

$\Rightarrow\ 81-\dfrac{6}{5}x\leq55$

Multiplying 5 on both the sides, we get

$5(81-\dfrac{6}{5}x)\leq5\times55\\\\\Rightarrow\ 405-6x\leq275\\\\\Rightarrow\ 6x\geq405-275\\\\\Rightarrow\ 6x\geq130\\\\\Rightarrow\ x\geq\dfrac{130}{6}\\\\\Rightarrow\ x\geq\dfrac{65}{3}\\\\\Rightarrow\ x\geq21\dfrac{2}{3}$