Answer:
In order to find the fraction of the 20 dollars that has been spent, we have to divide the amount spent by the total amount. So 0.65 is the fraction of 20 that is spent.
Step-by-step explanation:
Answer:
Not the smartest person, but the graph shows that they're pointing down!
Step-by-step explanation:
Answer:
is the fraction of 8th graders who are boys.
Step-by-step explanation:
Let total number of 8th graders = 
Given that, 
of 8th graders play sports
8th graders who play sports = 
Also, Given that, 
of 8th graders that play sports are boys
Number of 8th graders that play sports, and are boys = 
Hence, the answer is:
is the fraction of 8th graders who are boys.
Answer:
x = 41.67
Step-by-step explanation:
The above equation, would be simplified or divided into parts;
Therefore, the given equation becomes;
A/x = B/C
Where;
A = (15.2*0.25-48.51/14.7)
B = (13/44-2/11-5/66/2.50)1.2
C = 3.2+0.8(5.5-3.25)
x = unknown variable.
<u>Part A</u>
(15.2*0.25-48.51/14.7) = (15.2*0.25 - 3.3)
A = (3.8 - 3.3)
A = 0.5
<u>Part B</u>
(13/44-2/11-5/66/2.50)1.2 = (0.3 - 0.18 - 0.030) * 1.2
B = 0.09 * 1.2
B = 0.108
<u>Part C</u>
(3.2+0.8(5.5-3.25)
C = 4*(2.25)
C = 9
<em>Substituting the values into the equation, we have;</em>
0.5/x = 0.108/9
<em>Cross-multiplying, we have;</em>
9 * 0.5 = 0.108x
4.5 = 0.108x
x = 4.5/0.108
x = 41.67
Answer:
The circulation of the field f(x) over curve C is Zero
Step-by-step explanation:
The function 
and curve C is ellipse of equation
Theory: Stokes Theorem is given by:
Where, Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5CF1%26F2%26F3%5Cend%7Barray%7D%5Cright%5D)
Also, f(x) = (F1,F2,F3)
Using Stokes Theorem,
Surface is given by g(x) = 
Therefore, tex]\hat{N} = grad(g(x))[/tex]
Now,
Curl f(x) =
Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5Cx%5E%7B2%7D%264x%26z%5E%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Curl f(x) = (0,0,4)
Putting all values in Stokes Theorem,
I=0
Thus, The circulation of the field f(x) over curve C is Zero
