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Burka [1]
3 years ago
14

A hill that has a 36.1% grade is one that rises 36.1 m vertically for every 100.0 ml of distance in the horizontal direction. At

what angle is such a hill inclined above the horizontal?
Physics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

angle is 19.85°

Explanation:

given data

grade = 36.1 %

vertically distance y = 36.1 m

horizontal distance x = 100 m

to find out

angle

solution

we know that according to question here

it make a triangle shape that contain 100 m base and height 36.1 m

and make angle with base is θ

so by triangle we know here

tanθ = y/x   ..........1

so we now put x and y and find θ

tanθ = 36.1 / 100

tanθ = 0.361

θ = 19.85°

so angle is 19.85°

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A pulse of light takes 3.00 ns to travel through air from an emitter to a detector. When a piece of transparent material with a
cupoosta [38]

Answer:

(a) 1.75\times10^8\text{ m/s}

(b) 1.71

Explanation:

(a) The difference in the times of travel in the two case = 3.20 - 3.00 = 0.20\text{ ns} = 2.0\times10^{-9}\text{ s}

This difference is the time in the transparent material. With a thickness of 35.0 cm, the speed in the material is

v = \dfrac{35 cm}{2.0\times10^{-9}\text{ s}}=\dfrac{0.35 m}{2.0\times10^{-9}\text{ s}} = 1.75\times10^8\text{ m/s}

(b) The refractive index of the material is the ratio of the velocity of light in  vacuum to its velocity in the material. Using speed of light in vacuum as c = 3.00\times10^8\text{ m/s}, the refractive index, n, is

n=\dfrac{c}{v} = \dfrac{ 3.00\times10^8\text{ m/s}}{1.75\times10^8\text{ m/s}}= 1.71

4 0
3 years ago
A stone is thrown with an initial speed of 11.5 m/s at an angle of 50.0 above the horizontal from the top of a 30.0-m-tall build
rewona [7]

Answer:

The magnitude of the horizontal displacement of the rock is 7.39 m/s.

Explanation:

Given that,

Initial speed = 11.5 m/s

Angle = 50.0

Height = 30.0 m

We need to calculate the horizontal displacement of the rock

Using formula of horizontal component

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=11.5\times\cos50

v_{x}=7.39\ m/s

Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.

8 0
3 years ago
2 kids are running down the hall at 2 m/s, one is 40kg and the other is 50kg (p=ma)
Georgia [21]

The net force acting on the two (2) kids is equal to 180 Newton.

<u>Given the following data:</u>

  • Mass of kid 1 = 40 kilogram.
  • Mass of kid 2 = 50 kilogram.
  • Acceleration = 2 m/s^2

To determine the net force acting on the two (2) kids:

First of all, we would calculate the total mass of the two (2) kids:

Total\;mass = 50+40

Total mass = 90 kg.

<h3>How to calculate net force.</h3>

In this exercise, you're required to calculate the magnitude of the net force that is acting on these two (2) kids running down the hall. Thus, we would apply Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by this formula;

Net\;force = mass \times acceleration

Substituting the given parameters into the formula, we have;

Net\;force = 90 \times 2

Net force = 180 Newton.

Read more on acceleration here: brainly.com/question/1121817

7 0
3 years ago
Please help. what's the answer??
Anvisha [2.4K]
I THINK it is C. KEYWORD is THINK
5 0
3 years ago
The Kentucky Derby is a 1¼ mile race. Mandaloun ran it in 1.52 minutes. Hot Rod Charlie ran at a speed of .79 miles per minute.
artcher [175]

Answer:

Mandaloun won the race.

Explanation:

First, we will calculate the time taken by the Hot Rod Charlie:

s = vt\\t = \frac{s}{v}

where,

t = time taken by Hot Rod Charlie = ?

s = distance covered = 1.25 miles

v = speed of Hot Rod Charlie = 0.79 miles/min

Therefore,

t = \frac{1.25\ miles}{0.79\ miles/min} \\t = 1.58 min

Since Hot Rod Charlie took more time (1.58 min) than the Mandaloun (1.52 min).

<u>Therefore Mandaloun won the race.</u>

6 0
3 years ago
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