The final velocity of the passenger is zero as he is brought to rest by the inflated bag.

Apply the equation of motion

Replacing with our values,



Calculate the force using the force equation,



Therefore the magnitude of force acts on the passenger's upper torso is 34.923kN
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Answer:
3335400 N/m² or 483.75889 lb/in²
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
A = Area = 1.5 cm²
m = Mass of woman = 51 kg
F = Force = mg
When we divide force by area we get pressure



The pressure exerted on the floor is 3335400 N/m² or 483.75889 lb/in²
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