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2 years ago

What force causes an automobile to move.

Physics

1 answer:

s2008m [1.1K]2 years ago

4 0

Answer:

Thrust

Explanation:

Thrust is the force that causes a car to move in the direction that it wants to.

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The moon is in a nearly circular orbit of radius r = 384000000 meters

PSYCHO15rus [73]

Answer:

$2.72\cdot 10^{-3} m/s^2$

Explanation:

The centripetal acceleration of an object in circular motion is the acceleration with which the object is attracted towards the center of the circular orbit. Mathematically, it is given by

$a=\frac{v^2}{r}$

where

v is the speed of the object

r is the radius of the orbit

The speed of the object is also given by the ratio between the circumference of the orbit and the orbital period, T:

$v=\frac{2\pi r}{T}$

Substituting into the previous equation, we find a new expression for the centripetal acceleration:

$a=\frac{4\pi^2 r}{T^2}$

In this problem:

- The radius of the orbit of the Moon is

$r = 384000000 m = 3.84\cdot 10^8 m$

- The period of the orbit is

$T=27.32 d \cdot 24\cdot 60\cdot 60 =2.36\cdot 10^6 s$

Therefore, the centripetal acceleration is:

$a=\frac{4\pi^2 (3.84\cdot 10^8)}{(2.36\cdot 10^6)^2}=2.72\cdot 10^{-3} m/s^2$

5 0

3 years ago

From the small number of impact craters on ____, planetary geologists suspect that virtually all its original surface has been c

allsm [11]

From the small number of impact craters on moon, planetary geologists suspect that virtually all its original surface has been covered over by younger volcanic activity. Most of the Moon's surface is densely covered with craters, but we find relatively few craters within the lunar maria.

3 0

4 years ago

In a food chain, which trophic level contains the greatest amount of energy?

evablogger [386]

I believe the correct answer from the choices listed above is option B. In a food chain. it is the producers trophic level that contains the greatest amount of energy since it is the very start of the chain. Most of the energy are being stored and passed to the next organism. Hope this answers the question.

6 0

3 years ago

A cyclist travelled 32 kilometers for both the 1st and 2nd hours. He took a 30 minute break to eat his lunch. He then travelled

Reika [66]

Answer:

The cyclist's average speed is 13.43 $\frac{km}{h}$

Explanation:

Speed is a quantity that expresses the relationship between the space traveled by an object and the time used for it. That is, speed is the magnitude that expresses the variation in position of an object and as a function of time, which would be the same as saying that it is the distance traveled by an object in the unit of time.

Average speed relates the change in position to the time taken to effect that change:

$speed=\frac{change in position}{time} =\frac{distance}{time}$

In this case:

total distance traveled= 32 km + 15 km= 47 km
total time= 3 hours that the cyclist travels + 30 minutes of rest = 3 hours + 0.5 hours (being 60 minutes equal to 1 hour, then 30 minutes equals 0.5 hours) = 3.5 hours

Replacing:

$speed=\frac{47 km}{3.5 h}$

and solving, you get:

speed= 13.43 $\frac{km}{h}$

The cyclist's average speed is 13.43 $\frac{km}{h}$

3 0

3 years ago

A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten

babymother [125]

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

$P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2$

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

8 0

4 years ago