Nitric oxide gas reacts with hydrogen gas to form ammonia gas and water vapor.
1 answer:
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Answer:
200 g C₆H₁₂O₆
General Formulas and Concepts:
<u>Chemistry - Solutions</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define</u>
1 M C₆H₁₂O₆
1 L of solution
<u>Step 2: Identify Conversions</u>
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
<u>Step 3: Find moles of solute</u>
1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L
x = 1 mol C₆H₁₂O₆
<u>Step 4: Convert</u>
<u /> = 180.18 g C₆H₁₂O₆
<u>Step 5: Check</u>
<em>We are given 1 sig figs. Follow sig fig rules and round.</em>
180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆
Answer:
A. c. Keq=[H2]^2[S2]/[H2S]^2
B. b. Keq=[COCl2]/[CO][Cl2]
Explanation:
Hello,
In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:
A. For the reaction:
The equilibrium expression is:
Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.
B. For the reaction:
The equilibrium expression is:
Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].
Regards.