Many grams of aluminum are required to produce 3.5 moles Al2O3 in the presence of excess O2?
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Hello!
The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ
To calculate Hrxn we apply the following equation:
Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction releases energy in the form of heat and that the reaction is exothermic.
Have a nice day!
The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ
To calculate Hrxn we apply the following equation:
Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction releases energy in the form of heat and that the reaction is exothermic.
Have a nice day!