Answer:
89.6 L.
Explanation:
- For the balanced reaction:
<em>CS₂ + 3O₂ → CO₂ + 2SO₂.</em>
- It is clear that <em>1.0 mole of CS₂</em> with 3.0 moles of O₂ to produce 1.0 mole of CO₂ and <em>2.0 moles of SO₂.</em>
<em></em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CS₂ produces → 2.0 moles of SO₂.
2.0 mole of CS₂ produces → ??? moles of SO₂.
∴ The no. of moles of SO₂ produced = (2.0 mol)(2.0 mol)/(1.0 mol) = 4.0 mol.
- It is known that 1.0 mole of any gas at STP occupies 22.4 L.
<em>∴ 4.0 moles of SO₂ occupy = (4.0)(22.4 L) = 89.6 L.</em>
<em></em>
Answer:
The mass of NaHCO3 required is 235.22 g
Explanation:
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Continuation of Question:
2NaHCO3(s) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)
You estimate that your acid spill contains about 1.4 mol H2SO4. What mass of NaHCO3 do you need to neutralize the acid?
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The question requires us to calculate the mass of NaHCO3 to neutralize the acid.
From the balanced chemical equation;
1 mol of H2SO4 requires 2 mol of NaHCO3
1.4 would require x?
Upon solving for x we have;
x = 1.4 * 2 = 2.8 mol of NaHCO3
The relationship between mass and number of moles is given as;
Mass = Number of moles * Molar mass
Mass = 2.8 mol * 84.007 g/mol
Mass = 235.22 g
The answer is C. Energy is released
If I understand correctly it would be answer choice A. "None"
Though I have not done this type of Science In a few years so My answer may be wrong.
Answer:
aw baby nah that ain't gonna work
points xx
Explanation: