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Bezzdna [24]
3 years ago
5

What is the energy change that will occur when 25.5 grams of oxygen gas (O2) react with excess methane (CH4) according to the re

action below?
CH4 + 2 O2yields CO2 + 2 H2O delta H = -889 kJ/mol

Select one:
a. 354 kJ of energy will be given off by the reaction
b. 354 kJ of energy will be absorbed by the reaction
c. 708 kJ of energy will be given off by the reaction
d. 708 kJ of energy will be absorbed by the reaction
Chemistry
1 answer:
AysviL [449]3 years ago
7 0
Amount of CH4 is excess, so no need to worry about it 
<span>but the limiting factor is the Oxygen </span>

<span>according to stranded equation, </span>

<span>CH4 + 2 O2 --> CO2 + 2 H2O ΔH = -889 kJ/mol </span>


<span>just by taking proportions </span>

<span>(-889 kJ/mol) / 2 x 0.8 mol = - 355.6 kJ </span>

<span>so i think the answer is (a)</span>
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What part of the atom is responsible for the behavior of the alpha particles?
ivann1987 [24]

Answer:

nucleus

Alpha particles are subatomic fragments consisting of two neutrons and two protons. Alpha radiation occurs when the nucleus of an atom becomes unstable (the ratio of neutrons to protons is too low) and alpha particles are emitted to restore balance.

Explanation:

8 0
3 years ago
70 points and will give brainliest
ikadub [295]

Answer:

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid  = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

       Equation of the reaction:

            C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

  • We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
  • From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
  • We find the number of moles of the baking powder that went into the reaction using the expression below:

                Number of moles = \frac{mass}{molar mass}

                Number of moles =  \frac{15}{84} = 0.179mole

  • From the equation of the reaction, we can find the number of moles of the citric acid:

             3 moles of baking powder reacted with 1 mole of citric acid

 0.179 moles of baking powder would react with \frac{0.179}{3}:

          This yields 0.059mole of citric acid

  • To find the volume of the citric acid, we use the mole expression below:

    Volume of citric acid = \frac{number of moles}{concentration}

Volume of citric acid = \frac{0.059}{0.8} = 0.074L

Expressing in mL gives 74mL

               

4 0
3 years ago
Explain why the available amount of water per person differs between countries
Fudgin [204]

Answer:

because in the different countries it is distributed unevenly.

Explanation:

hope this helps

4 0
2 years ago
Read 2 more answers
How many grams of NaCl (molecular weight = 58 Da) would you have to dissolve in 50ml to make a 2M stock solution? Answer:
Lerok [7]

Answer:

5.8 g

Explanation:

Molecular weight in Daltons is equivalent to the molecular weight in grams per mole.

The amount of NaCl required is calculated as follows:

(2 mol/L)(50 mL)(1 L/1000 mL) = 0.1 mol

This amount is converted to grams using the molar mass (58 g/mol).

(0.1 mol)(58 g/mol) = 5.8 g

7 0
3 years ago
Which of the following statements best describes why a solution of 6.00 g of Ca(NO3)2?in 30.0 g of water has a greater boiling-p
sukhopar [10]
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That means, the the boiling-point elevation depends on the molar content (fraction) of solute.

The dependency is ΔTb = Kb*m

Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.

A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:

(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg =   50/molar mass

=> 200 / 50 = 4.

Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g  of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.

Or, what is the same, the solution with higher molality will have the higher boiling point.
5 0
3 years ago
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