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arsen [322]
2 years ago
12

How many ions in 6.41 moles of K2O? Please show work.

Chemistry
1 answer:
Oksana_A [137]2 years ago
4 0
1. Convert the number of moles to number of particles (divide 6.41 by 6.022 x 10^23)

2. K2O dissociates into three ions (2 potassium ions and 1 oxide ion), so multiply the result from step 1 by 3 to get your answer
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Mercury is the only metal that is a liquid at room temperature. When mercury vapor is inhaled, it is readily absorbed by the lun
Lapatulllka [165]

Answer:

P = 0.0166 mm Hg

Explanation:

To solve this question, we need to use the Clausius Clapeyron equation, which is a commonly used expression to calculate vapour pressure at a given temperature. We have the enthalpy of vaporization of the mercury, so, let's write the equation:

Clausius Clapeyron equation:

Ln (P₂ / P₁) = (-ΔHv / R)(1/T₂ - 1/T₁)    (1)

Where:

R: universal constant of gases (8.314 J / K.mol)

P₂: Vapour pressure at 43°C (or 316 K)

P₁: Pressure of mercury at the boiling point (1 atm)

T₂: temperature at 43 °C

T₁: Boiling point of mercury (357 °C or 630 K)

As we are given the boiling point of the mercury, we can safely assume that the pressure at this point is 1 atm, becuase remember that when a sustance boils, is because it's internal pressure has reached the atmospherical pressure of 1 atm. With this clear, all we just need to do is solve for P₂. We are going to do this very slowly so you can understand the process. First let's replace the given data:

Ln (P₂ / 1) = (-59100 J/mol / 8.314 J / K.mol) (1/316 - 1/630)

Ln P₂ = -7108.49 * (3.16x10⁻³ - 1.59x10⁻³)

Ln P₂ = -7108.49 * (1.51x10⁻³)

Ln P₂ = -10.7338

P₂ = 10⁽⁻¹⁰°⁷³³⁸⁾

P₂ = 2.18x10⁻⁵ atm

We can express this value in mm Hg and it will be:

P₂ = 2.18x10⁻⁵ * 760

<h2>P₂ = 0.0166 mm Hg</h2>

Hope this helps

8 0
2 years ago
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Answer:

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These are the reactants in the chemical equation 2 H2 + 02 --> 2 H2O: 2H2 and O2

These are the reactants in the chemical equation 2 H2O --> 2 H2 + O2: 2H2O

4 0
2 years ago
Which of the following chemical equations represents an oxidation-reduction reaction?
zimovet [89]
C. Represents an oxidation-reduction reaction
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3 years ago
Conociendo el volumen de la solución y la masa del soluto y su masa molar, ¿qué concentración es posible determinar
NISA [10]

Answer:

Conociendo el volumen de solución, masa de soluto y su masa molar, es posible determinar: B) Concentración molar

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M = No moles de solución de soluto / volumen (L)

Y a su vez los moles de soluto se encuentran por:

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8 0
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Answer:

Ei

Explanation:

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3 years ago
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