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Alex_Xolod [135]
3 years ago
12

A.) write an equation in slope intercept form for the total cost of any number of tickets at 7 tickets for $5.

Mathematics
1 answer:
MrMuchimi3 years ago
7 0
Slope intercept form is y = mx + b

7 tickets for $5 means that 1 ticket costs 5/7 dollars

So for part a, the slope intercept form would be:

y = \frac{5}{7}x

where x is the number of tickets, and y is the price.

For part b)

The slope intercept form is:
y = 25x

where x is the number of all you can ride wristbands you buy, and y is the total price.

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The difference of the product of 3 and 6 minus the quotient of 6 divided by 2
Xelga [282]

Answer:

15

Step-by-step explanation:

3*6 - 6/2

18 - 3

15

4 0
2 years ago
Look for a pattern for the decimal 0.555, the value of the digit in the tenths place is how many times as munch as the value of
Galina-37 [17]
<span>the value of the digit in the tenths place is 5/10 or 0.5
</span>
the value of the digit in the thousandth place is 5/1000 = 0.005

0.5 = 100 x 0.005

Therefore, the value of the digit in the tenths place is 100 times as much as the value of the digit in the thousandth place
3 0
3 years ago
Amir is sorting his stamp collection. He has made a chart of what countries the stamps are from
natulia [17]

Answer:

Step-by-step explanation:

Given that Amir is sorting his stamp collection. He has made a chart of what countries the stamps are from

He got results as

France 1/3  

Morocco 5/12  

Spain 1/6

To find out what fraction of Amir's stamps are from France, Morocco, or Spain, we have to simply add the three as there is common element between any two pairs

Hence answer is

\frac{1}{3} +\frac{5}{12} +\frac{1}{6}\\ =\frac{11}{12}

8 0
3 years ago
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5 0
3 years ago
Find the unit tangent vector T(t) to the curve r(t) = [sin(t), 1 + t, cos(t)] when t = 0.
ss7ja [257]

Compute the derivative of \mathbf r(t) at t=0 - this will be the tangent vector - then normalize it by dividing it by its magnitude to get the unit tangent vector \mathbf T(t).

\mathbf r(t) = \langle \sin(t), 1+t, \cos(t) \rangle \implies \dfrac{d\mathbf r}{dt} = \langle \cos(t), 1, -\sin(t) \rangle \implies \dfrac{d\mathbf r}{dt}(0) = \langle 1, 1, 0 \rangle

\|\langle1,1,0\rangle\| = \sqrt{1^2+1^2+0^2} = \sqrt2

\implies\mathbf T(0) = \dfrac{\langle1,1,0\rangle}{\sqrt2} = \boxed{\left\langle \dfrac1{\sqrt2}, \dfrac1{\sqrt2}, 0\right\rangle}

7 0
2 years ago
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