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Anna35 [415]
3 years ago
8

F(x)=4x-1 G(x)=x+3 Find f(x)+g(x)

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0

Answer:

Answer is 5x+2

Step-by-step explanation:

Given \: f(x) = 4x - 1 \:  \: and \:  \\ g(x) = x + 3 \\ f(x) + g(x) = 4x -1    + x + 3 \\  = 5x + 2

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
maks197457 [2]

Answer:

The uncertainty in the average speed is 0.134 meters per second.

Step-by-step explanation:

Let be v(t, x) =\frac{x}{t} the average speed function, we calculate the uncertainty in the average speed by total differentials, which is in this case:

\Delta v = \frac{\partial v}{\partial x}\cdot \Delta x+\frac{\partial v}{\partial t}\cdot \Delta t

Where:

\Delta v - Uncertainty in the average speed, measured in meters per second.

\frac{\partial v}{\partial x} - Partial derivative of the average speed function with respect to distance, measured in s^{-1}.

\frac{\partial v}{\partial t} - Partial derivative of the average speed function with respect to time, measured in meters per square second.

\Delta x - Uncertainty in distance, measured in meters.

\Delta t - Uncertainty in time, measured in seconds.

Partial derivatives are, respectively:

\frac{\partial v}{\partial x} = \frac{1}{t}, \frac{\partial v}{\partial t} = - \frac{x}{t^{2}}

Then, the total differential expression is expanded as:

\Delta v = \frac{\Delta x}{t}-\frac{x\cdot \Delta t}{t^{2}}

If we get that \Delta x = 2.3\,m, t = 6.3\,s, x = 6.1\,m and \Delta t = 1.5\,s, the uncertainty in  the average speed is:

\Delta v = \frac{2.3\,m}{6.3\,m}-\frac{(6.1\,m)\cdot (1.5\,s)}{(6.3\,s)^{2}}

\Delta v = 0.134\,\frac{m}{s}

The uncertainty in the average speed is 0.134 meters per second.

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3 years ago
Solve each system using elimination.
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Https://www.mathpapa.com/algebra-calculator.html
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Bill jogged 1/6 longer than he swam.
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2 years ago
Find the solutions <br> x^2=16x-28
ioda
Minus 16x both sides and add 28 to both sides
x^2-16x+28=0
factor
hmm, what 2 numbers multiply to 28 and add to -16
hmm
1 and 28? nope
2 and 14? yep
since middle term is negative and last tem is positive, both of the factors are negative

(x-14)(x-2)=0
set each to zero
x-14=0
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x-2=0
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