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777dan777 [17]
3 years ago
12

The teacher in item 10 also needs to order plastic tubing. If each of the 60 students need 750 mm of tubing, what length of tubi

ng in meters should the teacher order?
Chemistry
1 answer:
Alex777 [14]3 years ago
6 0

45 m. If each student needs 750 mm of tubing, the teacher should order 45 m of tubing.

a) Find the <em>length in millimetres</em>

Length = 60 students x (750 mm tubing/1 student) = 45 000 mm tubing

b) Convert <em>millimetres to metres </em>

Length = 45 000 mm tubing x (1 m tubing/1000 mm tubing) = 45 m tubing

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Potassium permanganate as a symbol
Alexxx [7]

Answer: KMnO4-

Explanation:

You're looking at one potassium plus a polyatomic ion.

So K plus MnO4, equals:

KMnO4-

It also has a molar mass of 158.04 g/mol, I don't know if you need that, but I thought it would be nice to include it.

7 0
3 years ago
Magnesium and oxygen are likely to form a covalent bond between them. True or false??
zalisa [80]
False is the answer.
3 0
4 years ago
An automated filling machine is used to fill bottles with liquid detergent. A random sample of 20 bottles results in a sample va
taurus [48]

Answer:

No, there is no evidence that the manufacturer has a problem with underfilled or overfilled bottles, due that according our results we cannot reject the null hypothesis.

Explanation:

according to this exercise we have the following:

σ^2 =< 0.01 (null hypothesis)

σ^2 > 0.01 (alternative hypothesis)

To solve we can use the chi-square statistical test. To reject or not the hypothesis, we have that the rejection region X^2 > 30.14

Thus:

X^2 = ((n-1) * s^2)/σ^2 = ((20-1)*0.0153)/0.01 = 29.1

Since 29.1 < 30.14, we cannot reject the null hypothesis.

4 0
3 years ago
Read 2 more answers
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
4 years ago
Identify the ion ratios needed to form neutral compounds from the ions below. The metal ion (cation) is listed first, and the no
Natasha2012 [34]
To figure out the ratios of these compounds, it is important to remember that the charge of these compounds must be <em>neutral</em>.

So in order to make them neutral, you must have specific ratios:

Na^{+}: Br^{-}  =1:1; This is true because they both have a charge of magnitude of 1.

Al^{3+}: Cl^{-}=1:3; We need 3 chlorine atoms because we need to balance out the charge from the 3+ charge of aluminum - therefore since chlorine has a 1- charge, we need 3 atoms.

Mg^{2+}: O^{2-}=1:1; The charges of the magnesium (2+) are balanced with the oxygen charge (2-).

Al^{3+}: O^{2-}=2:3; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.

7 0
3 years ago
Read 2 more answers
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