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2 years ago

How is graphite structured?

1 answer:

4 0

Graphite is structured in a way that: (A). Its carbon atoms are bonded to 3 other carbon atoms and are structured in layers that can slip past each other.

<h3>Meaning of a graphite</h3>

A graphite can be defined as a crystalline form of carbon.

Graphite is so important to man as it is used in many industries and factories as well as many countries to produce different products that can help mankind.

Graphite structure is quite a complex one and it involve carbons that have three of its electrons bonded and one free.

In conclusion, Graphite is structured in a way that: Its carbon atoms are bonded to 3 other carbon atoms and are structured in layers that can slip past each other.

Learn more about Graphite: brainly.com/question/4061239

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What type of reaction is represented by the following chemical equation? Explain your answer. Thanks!:)

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DISPLACEMENT REACTION

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3 years ago

How many molecules are in 3 moles of NaCl?

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Answer:

Given : No. Of moles = 1.5

To calculate : no. Of molecules =N

We know that moles = N / 6.022 x 10²³

Therefore, 1.5 x 6.022 x 10²³ = N

Hence N = 9.0330x 10²³ molecules

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3 years ago

Which of the following statements is true of glare control?

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The correct option is B.
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3 years ago

Mangrove trees are affected by several factors. Which is an abiotic factor contributing to the energy cycle of a mangrove ecosys

kondor19780726 [428]

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3 years ago

Sulfuryl dichloride is formed when sulfur dioxide reacts with chlorine.

zubka84 [21]

<u>Answer:</u> The value of $\Delta G^o$ of the reaction is 28.38 kJ/mol

<u>Explanation:</u>

For the given chemical reaction:

$SO_2(g)+Cl_2(g)\rightarrow SO_2Cl_2(g)$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(SO_2Cl_2(g))})]-[(1\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(Cl_2(g))})]$

We are given:

$\Delta H^o_f_{(SO_2Cl_2(g))}=-364kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H^o_f_{(Cl_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-364))]-[(1\times (-296.8))+(1\times 0)]=-67.2kJ/mol=-67200J/mol$

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_f_{(product)}]-\sum [n\times \Delta S^o_f_{(reactant)}]$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(1\times \Delta S^o_{(SO_2Cl_2(g))})]-[(1\times \Delta S^o_{(SO_2(g))})+(1\times \Delta S^o_{(Cl_2(g))})]$

We are given:

$\Delta S^o_{(SO_2Cl_2(g))}=311.9J/Kmol\\\Delta S^o_{(SO_2(g))}=248.2J/Kmol\\\Delta S^o_{(Cl_2(g))}=223.0J/Kmol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(1\times 311.9)]-[(1\times 248.2)+(1\times 223.0)]=-159.3J/Kmol$

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

$\Delta G^o_{rxn}=\Delta H^o_{rxn}-T\Delta S^o_{rxn}$

where,

$\Delta H^o_{rxn}$ = standard enthalpy change of the reaction =-67200 J/mol

$\Delta S^o_{rxn}$ = standard entropy change of the reaction =-159.3 J/Kmol

Temperature of the reaction = 600 K

Putting values in above equation, we get:

$\Delta G^o_{rxn}=-67200-(600\times (-159.3))\\\\\Delta G^o_{rxn}=28380J/mol=28.38kJ/mol$

Hence, the value of $\Delta G^o$ of the reaction is 28.38 kJ/mol

7 0

3 years ago