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vazorg [7]
2 years ago
11

How is graphite structured?

Chemistry
1 answer:
yarga [219]2 years ago
4 0

Graphite is structured in a way that: (A). Its carbon atoms are bonded to 3 other carbon atoms and are structured in layers that can slip past each other.

<h3>Meaning of a graphite</h3>

A graphite can be defined as a crystalline form of carbon.

Graphite is so important to man as it is used in many industries and factories as well as many countries to produce different products that can help mankind.

Graphite structure is quite a complex one and it involve carbons that have three of its electrons bonded and one free.

In conclusion, Graphite is structured in a way that: Its carbon atoms are bonded to 3 other carbon atoms and are structured in layers that can slip past each other.

Learn more about Graphite: brainly.com/question/4061239

#SPJ1

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2Na(s) + 2H,O(l) — 2NaOH(?) + H, (g)<br> 0 what is the missing symbol
Klio2033 [76]

Answer:

the symbol that is missing might be 2.

Explanation:

I am not 100% on this, so correct me if I am wrong.

3 0
2 years ago
What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?
mr Goodwill [35]

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we <u>convert 166.00 g of KI into moles</u>, using its <em>molar mass</em>:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

  • 166.00 g ÷ 166 g/mol = 1 mol KI

Then we <u>calculate the required volume</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters

Liters = moles / molarity

  • 1 mol / 1.00 M = 1 L
3 0
3 years ago
Determine the number of ions produced in the dissociation of the compound listed. BaS
11Alexandr11 [23.1K]
BaS → Ba²⁺ + S²⁻
two types of ions
4 0
4 years ago
Read 2 more answers
A water treatment plant applies chlorine for disinfection so that 10 mg/L chlorine is achieved immediately after mixing. The vol
Vlada [557]

<u>Answer:</u> The mass of chlorine needed by the plant per day is 9.4625\times 10^8mg

<u>Explanation:</u>

We are given:

Volume o water treated per day = 25,000,000 gallons

Converting this volume from gallons to liters, we use the conversion factor:

1 gallon = 3.785 L

So, \frac{3.785L}{1\text{ gallon}}\times 25,000,000\text{ gallons}=9.4625\times 10^7L

Amount of chlorine applied for disinfection = 10 mg/L

Applying unitary method:

For 1 L of water, the amount of chlorine applied is 10 mg

So, for 9.4625\times 10^7L of water, the amount of chlorine applied will be \frac{10mg}{1L\times 9.4625\times 10^7L}=9.4625\times 10^8mg

Hence, the mass of chlorine needed by the plant per day is 9.4625\times 10^8mg

6 0
3 years ago
rate of a certain reaction is given by the following rate law: rate Use this information to answer the questions below. What is
Sunny_sXe [5.5K]

Complete Question

The  rate of a certain reaction is given by the following rate law:

            rate =  k [H_2][I_2]

rate Use this information to answer the questions below.

What is the reaction order in H_2?

What is the reaction order in I_2?

What is overall reaction order?

At a certain concentration of H2 and I2, the initial rate of reaction is 2.0 x 104 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled? Round your answer to significant digits. The rate of the reaction is measured to be 52.0 M / s when [H2] = 1.8 M and [I2] = 0.82 M. Calculate the value of the rate constant. Round your answer to significant digits.

Answer:

The reaction order in H_2 is  n =  1

The reaction order in I_2 is  m = 1

The  overall reaction order z =  2

When the hydrogen is double the the initial rate is   rate_n  =  4.0*10^{-4} M/s

The rate constant is   k = 35.23 \  M^{-1} s^{-1}

Explanation:

From the question we are told that

   The rate law is  rate =  k [H_2][I_2]

   The rate of reaction is rate =  2.0 *10^{4} M /s

Let the reaction order for H_2 be  n and for I_2  be  m

From the given rate law the concentration of H_2 is raised to the power of 1 and this is same with I_2 so their reaction order is  n=m=1

   The overall reaction order is  

               z  = n +m

               z  =1 +1

               z  =2

At  rate =  2.0 *10^{4} M /s

        2.0*10^{4}  = k  [H_2] [I_2] ---(1)

= >    k  = \frac{2.0*10^{4}}{[H_2] [I_2]  }

given that the concentration of hydrogen is doubled we have that

            rate  = k [2H_2] [I_2] ----(2)

=>      k = \frac{rate_n  }{ [2H_2] [I_2]}

 So equating the two k

           \frac{2.0*10^{4}}{[H_2] [I_2]  } = \frac{rate_n  }{ [2H_2] [I_2]}

    =>    rate_n  =  4.0*10^{-4} M/s

So when

      rate_x =  52.0 M/s

        [H_2] = 1.8 M

         [I_2] =  0.82 \ M

We have

      52 .0 =  k(1.8)* (0.82)

     k = \frac{52 .0}{(1.8)* (0.82)}

      k = 35.23 M^{-2} s^{-1}

     

     

3 0
3 years ago
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