the reaction between HA and NaOH, HA(aq) + NaOH(aq) → NaA(aq) + H₂O(l)
the stoichiometric ratio between HA and NaOH is 1 : 1 Hence, Moles of NaOH added = reacted moles of HA in 25.00 mL
Moles of NaOH added = concentarion x volume added = 0.104 mol L⁻¹ x 21.70 x 10⁻³ L
reacted moles of HA in 25.00 mL = 0.104 mol L⁻¹ x 21.70 x 10⁻³ L hence, the initial [HA] = moles / volume = (0.104 mol L⁻¹ x 21.70 x 10⁻³ L) / 25.00 x 10⁻³ L = 0.090 M
According to the pH, the molar solubility = [H⁺(aq)] = X
pH = -log[H⁺(aq)] 3.70 = -log[H⁺(aq)] [H⁺(aq)] = 1.995 x 10⁻⁴ M X = 1.995 x 10⁻⁴ M
at equilibrium, HA(aq) ⇄ H⁺(aq) + A⁻(aq) Initial 0.090 Change -X +X +X Equilibrium 0.090 - X X X
Ka = [H⁺(aq)] [ A⁻(aq)] / [HA(aq)] = X x X / (0.090 - X) = (1.995 x 10⁻⁴ M)² / (0.090 - 1.995 x 10⁻⁴) M = 4.432 x 10⁻⁷ M
You would most likely see rolling grasslands. There would be isolated trees and shrubs. Not enough rain falls in the savanna to support forests. :) hope this helps
