Answer:
Step-by-step explanation:
Given :
In the given quadrilateral ABCD,
BN and DM are the perpendiculars drawn to AC such that,
BN = DM
To prove:
Point O is the midpoint of segment BD.
Or
OD = OB
Solution:
In ΔOMD and ΔONB,
∠MOD ≅ NOB [Vertical angles]
∠M ≅ ∠N ≅ 90° [Given]
Therefore, by AA property of similarity,
ΔOMD ~ Δ ONB
Therefore, their corresponding sides will be proportional,

Since BN = DM,
OD = OB
Hence O is the midpoint of BD.
Answer:
See below
Step-by-step explanation:
1: (b+1)*(3b)*(b-5)
(3b^2+3b)(b-5)
3b^3-15b^2+3b^2-10b
3b^3-12b^2-10b
2: πr^ 2(h/3)
π(n-2)^2(12n/3)
π(n-2)(n-2)(12n/3)
π(n^2-2n-2n+4)(12n/3)
π(n^2-4n+4)(12n/3)
π(n^2-4n+4)(4n)
π(4n^3-16n^2+16n)
<em>(I'm not 100% sure with this one)</em>
3: (lwh)/3
((k-2)(2k+3)(3k))/3
((2k^2-4k+3k-6)(3k))/3
(6k^3-12k^2+9k^2-18k)/3
(6k^3-3k^2-18k)/3
2k^3-k^2-6k
There are 14 positions. There are 266 choices for the first juror, 265 for the second, 264 for the third, etc. 266*265*264*...*252=<span>5.93893009829e+33, or about 6,000,000,000,000,000,000,000,000,000,000,000 complete juries. Hope this helps!</span>
Answer:
13/100 sorry thats the simplest its kind of obvious..