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kirill [66]
3 years ago
11

If a axbxc=0, and a and b are integers greater than 10, what must c equal

Mathematics
2 answers:
V125BC [204]3 years ago
8 0
I think 0.... becuase axbxc=0 and notig else can be the right answer....I hope
Nutka1998 [239]3 years ago
3 0

Answer:

The value of c is zero.

Step-by-step explanation:

We are given the following information in the question:

a\times b\times c = 0

It is also given that a and are integers such that:

a, b > 10

Thus, c must be equal to 0.

  • The multiplication property states that the product of any number and zero is zero.
  • It doesn't matter what the number is, when you multiply the number to zero, the answer is always zero.

Hence, the value of c is zero.

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jenny peddled her bike for 11 miles in 45 minutes if she traveled the same speed how far would she reach in 2 hours?
professor190 [17]
60 * 2 = 120
120 / 45 = 2.6...7
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Messed that up!

11 / 45 = .24...
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3 years ago
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There is a L-shaped sidewalk that is 158 meters long. By cutting across the lawn, the
NikAS [45]

Answer:

Each side of the L-shaped sidewalk is 126 m and 32m respectively.

Step-by-step explanation:

Given:

Total length of the sidewalk = 158 meters

Cutting across the lawn the distance = 130 meters

The L-shaped lawn will be treated as a right angled triangle.

So the 130 m distance is the hypotenuse here.

Let one side of the L-shaped lawn be 'x' meter so the another side will be (158-x) meters.

Applying Pythagoras formula.

(Hypotenuse)^2=(height)^2+(base)^2

So,

⇒ (130)^2=x^2 +(158-x)^2

⇒ (130)^2=x^2+(158-x)(158-x)

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Applying quadratic formula;

Quadratic formula : \frac{\pm b \sqrt{b^2-4ac} }{2a} where a=1 and b=-158 and c=4032

So the value of x= 126 and 32.

The length of each side of the sidewalk is 'x'= 126 m and '(158-x)'='(158-126)'=32 m

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3 years ago
Given that f(x) = 5x - 10 and g(x) = x + 3, find f(g(-1)).
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ElenaW [278]
A number times 1 always equals itself, so: 4×1 = 4, OR 2×2 = 4
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