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kifflom [539]
4 years ago
11

To prepare 250 grams of an aqueous KI solution that is 24.0% by weight of this solute how many grams of water and how many grams

of KI are used?
Chemistry
1 answer:
Ede4ka [16]4 years ago
6 0

190 g of water

60 g of KI

Explanation:

For concentration expressed in mass percentage of the solution we have the following formula:

concentration / 100 = mass of the dissolved / mass of the solution

mass of the dissolved KI = (concentration × mass of the solution) / 100

mass of the dissolved KI = (24 × 250) / 100 = 60 g

mass of the solution = mass of the water + mass of the dissolved KI

mass of the water = mass of the solution - mass of the dissolved KI

mass of the water = 250 - 60 = 190 g

Learn more about:

mass percent concentration

brainly.com/question/7291819

#learnwithBrainly

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The new temperature of the gas is 427K

Explanation:

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3 years ago
How many kilowatt-hours of electricity are used to produce 3.00 kg of magnesium in theelectrolysis of molten MgCl2 with an appli
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There is 29.8 kilowatt hours needed.

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Step 2: Calculate moles of Magnesium

Moles = Mass Mg / Molar mass Mg

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Step 3: Calculate  how many electrons are needed to produce the magnesium.

The ionic equation for the reduction of Mg^2+ :

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Step 3: Find how many coulombs are involved.

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1 mole of electrons is 96500 coulombs.

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