The percentage yield is 72.8 %.
<em>Step 1</em>. Calculate the <em>mass of Br₂</em>
Mass of Br₂ = 20.0 mL Br₂ × (3.10 g Br₂/1 mL Br₂) = 62.00 g Br₂
<em>Step 2</em>. Calculate the <em>theoretical yield</em>
M_r: 159.81 266.69
2Al + 3Br₂ → 2AlBr₃
Moles of Br₂ = 62.00 g Br₂ × (1 mol Br₂/(159.81 g Br₂) = 0.3880 mol Br₂
Moles of AlBr₃ = 0.3880 mol Br₂ × (2 mol AlBr₃/(3 mol Br₂) = 0.2586 mol AlBr₃
Theor. yield of AlBr₃ = 0.2586 mol AlBr₃ × 266.99 g AlBr₃)/(1 mol AlBr₃)
= 69.05 g AlCl₃
<em>Step 3</em>. Calculate the <em>percentage yield
</em>
% yield = (actual yield/theoretical yield) × 100 % = (50.3 g/69.05 g) × 100 %
= 72.8 %
Answer:
A.) 8.796 B.) 234780 C.) 25.8
Explanation:
thats all i can read the rest is blurry
Answer:
125g
Explanation:
you simply add the masses together
Answer: at low pressure and high temperature.
The real gases deviate from ideal gases at high pressures and low temperatures, because high pressure and low temperatures reduce the free space between the particles and their velocities, causing that the effect of the volume of the particles of the gas and the intermolecular forces be more important.
The lower the pressure and the higher the temperatures the less the effect of the volume of the particles and of the intermolecular forces. Remember that ideal gas theory considers that individual particles do not occupy space and they do not intereact one to each other (except for the collisions).
Answer:
uff mere dil ma ture kali chadiya ha uff tumi apne buni ha
