Answer:
The given sample is aluminum.
Explanation:
Given data:
Mass of unknown sample = 54 g
Volume of given sample = 20cm³
Is sample is Al = ?
Solution:
In order to solve this problem we must know the density of Al from literature.
density of Al = 2.7 g/cm³
Now we will calculate the density of given unknown sample.
d = m/v
d = 54 g/ 20cm³
d = 2.7 g/cm³
Thus given sample is aluminum.
The given condition is STP, under this condition, gas has a rule of 22.4 L per mole. And the given equation is already balanced. The ratio of mole number is the same as the ratio of the volume and is also the same as the ratio of coefficients. So the answer is 4.0 liters.
Answer:
19.6 g is the mass of methanol
Explanation:
Density of methanol is 0.787 g/mL.
Density means mass / volume
Methanol density = Methanol mass / Methanol volume.
Let's replace in the formula
0.787 g/mL = Methanol mass / 25 mL
0.787 g/mL . 25 mL = Methanol mass → 19.6 g