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3 years ago

Complete the table using the rule 2x - y = 4 x 3 4 5 25 34 y _ _ _

Mathematics

1 answer:

Sophie [7]3 years ago

3 0

Answer:

Step-by-step explanation:

2x - y = 4

2(3) - y = 4

6 - y = 4

-y = 4 - 6

-y = -2

y = 2

2x - y = 4

2(4) - y = 4

8 - y = 4

-y = 4 - 8

-y = -4

y = 4

2x - y = 4

2(5) - y = 4

10 - y = 4

-y = 4 - 10

-y = -6

y = 6

2x - y = 4

2(25) - y = 4

50 - y = 4

-y = 4 - 50

-y = -46

y = 46

2x - y = 4

2(34) - y = 4

68 - y = 4

-y = 4 - 68

-y = -64

y = 64

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4 years ago

The second term is 8 and the fifth term is -27. Find a1 in this geometric sequence.

Kay [80]

Answer:

$a_{1} = \frac{-16}{3}$

Now the Geometric sequence

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Step-by-step explanation:

Step(i):-

Given second term is '8'

$t_{n}= a r^{n-1}$

$t_{2}= a r^{2-1}$

$a r^{2-1} = 8$

a r = 8 ...(i)

And also given fifth term is -27

$t_{5}= a r^{5-1}$

$a r^{4} = -27$ ...(ii)

Step(ii):-

Now simplify

$\frac{a r^{4} }{ar} = \frac{-27}{8}$

$r^{3} = \frac{-27}{8}$

$r^3 =\frac{(-1)^{3} (3)^{3} }{(2)^{3} }$

$(r^3)^{\frac{1}{3} } =(\frac{(-1)^{3} (3)^{3} }{(2)^{3} })^{\frac{1}{3} }$

On simplification, we get

$r = \frac{-3}{2}$

now from(i)

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$a = \frac{-16}{3}$

$a_{1} = \frac{-16}{3}$

Now the Geometric sequence

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3 years ago

Complete the table using the rule 2x - y = 4 x 3 4 5 25 34 y _ _ _ __ __

Complete the table using the rule 2x - y = 4 x 3 4 5 25 34 y _ _ _