<h3>
Answer: 31 degrees</h3>
This is because rotations preserve angles. The angle measures won't change. That's why angle BCD is the same as angle B'C'D'. This applies to any rotation (regardless how much you rotate), any translation, any reflection, and any dilation.
Note: dilations will change the side lengths
Answer:
Slope:
y-intercept: 
Step-by-step explanation:
The equation of the line in Slope-Intercept form is:

Where "m" is the slope and "b" is the y-intercept.
The slope can be found with the following formula:

In this case you can say that:

Knowing this values you can substitute them into the formula and then evaluate, in order to find the slope. This is:

By definition, the line intersects the y-axis when the value of "x" is 0.
Notice in the table that when
, 
Therefore, the y-intercept is:

Answer:b
Step-by-step explanation:
(×+1)(×-1)
---------------
(×+1)(×+7)
=cancel (×+1) both the numerator and denominator then you are left with
(×-1)
-------
(×+7)
=(×-1)/(×+7)
After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.
After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.
And so on. After t years, the investment would have a value of
.
We want the find the number of years n such that

Solve for n :




