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nirvana33 [79]
3 years ago
12

For algraha 1 Don’t mine what I wrote

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
The answer for this equation is 0
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(9.5•10/11)+(6.3•10/9
maria [59]
15 7/11 I think im not sure
5 0
3 years ago
Read 2 more answers
You fill a 100 mL graduated cylinder with 38.5 mL of water. What is the volume?
larisa [96]

Answer:

38.5cm³

Step-by-step explanation:

1ml = 1cm³

38.5ml = 38.5cm³

7 0
3 years ago
Plss help for brainlist
luda_lava [24]

Answer:

{2, 4, 6}

Step-by-step explanation:

the domain is the interval or set of valid x (input) values.

the range is the interval or set of valid y (result) values.

just use the x values in the functional definition and collect the results. these are the range.

x = -1

y = 2×-1 + 4 = 2

x = 0

y = 2×0 + 4 = 4

x = 1

y = 2×1 + 4 = 6

3 0
3 years ago
2, 5, 25/2<br> ​ <br> ,...<br> Find the 9th term.
Cloud [144]

Step-by-step explanation:

seems to be multiplication, because the differences between the numbers change.

so, let's find the factor.

2 × f = 5

f = 5/2

5 × f = 5 × 5/2 = 25/2

ok, the factor 5/2 is confirmed.

a1 = 2

a2 = a1 × 5/2 = 2 × 5/2 = 10/2 = 5

a3 = a2 × 5/2 = a1 × 5/2 × 5/2 = 2 × 5/2 × 5/2 = 25/2

an = an-1 × 5/2 = a1 × (5/2)^(n-1) = 2 × (5/2)^(n-1)

a9 = 2 × (5/2)⁸ = 2 × 390,625/256 =

= 390,625/128 = 3,051.7578125

8 0
2 years ago
The expression (x^3)(x^-17) is equivalent to x^n. what is the value of n record your answer and fill in the bubbles on the answe
bekas [8.4K]

Exercise 1:

The exponents are wrong: when you divide two power, you subtract the exponents:

\dfrac{54x^9y^8}{6x^3y^4} = \dfrac{54}{6}x^{9-3}y^{8-4} = 9x^6y^4

Exercise 2:

The function represents a growth rate of 300%! 3% is actually written as 0.03, so the correct function is

78000\cdot 0.03^x

Exercise 3:

To factor a quadratic equation, we have to find the roots. Once you have the roots m_1, m_2, you can factor the expression as (m-m_1)(m-m_2)

In this case, the solutions are m=-2,\ m=15, which yields the factorization

(m+2)(m-15)

Exercise 4:

When you multiply two powers of the same base, you add the exponents:

a^b\cdot a^c = a^{b+c}

So, in your case, you have

x^{3}\cdot x^{-17} = x^{3-17} = x^{-14}

4 0
3 years ago
Read 2 more answers
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