<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Find the greatest common factor and then divide each number by it.
in this case the gcf for 75 and 100 is 25.
75 divided by 25 = 3
100 divided by 25 = 4
so 75/100 simplified = 3/4
Answer: The required values are
x = 12 units, ST = 60 units and SU = 120 units.
Step-by-step explanation: Given that T is the midpoint of SU, where
ST = 5x and TU = 3x + 24.
We are to find the values of x, ST and SU.
Since T is the midpoint of SU, so we get
So, the value of x is 12.
Therefore,
and
Thus, the required values are
x = 12 units, ST = 60 units and SU = 120 units.
5x+x=300
6x=300
x=50
5(50)=250 (Rose)
x=50(John)
Rose has 250 stickers and John has 50, therefore Rose has 200 more stickers than John.
How many class members are there??
