A = lw - s²
A = (x + 10)(2x + 5) - (x + 1)²
A = (x(2x + 5) + 10(2x + 5)) - (x + 1)(x + 1)
A = (x(2x) + x(5) + 10(2x) + 10(5)) - (x(x + 1) + 1(x + 1))
A = (2x² + 5x + 20x + 50) - (x(x) + x(1) + 1(x) + 1(1))
A = (2x² + 25x + 50) - (x² + x + x + 1)
A = (2x² + 25x + 50) - (x² + 2x + 1)
A = (2x² - x²) + (25x - 2x) + (50 - 1)
A = x² + 23x + 49
Since you are given the angle 110 degrees, you subtract that from 180 and get 70 so angle 1 is 70 degrees
Answer:
B
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile.
The upper quartile ( right end of box ) = 54
The lower quartile ( left end of box ) = 42
Interquartile range = 54 - 42 = 12 → B
Answer:
No.
Step-by-step explanation:
No, Bob is not correct.
The formula he's using is the following:
The important thing here is that the angle is between the two sides.
In the given triangle, 120 is not between 8 and 18. Therefore, using this formula will not be valid.
Either Bob needs to find the other side first or find the angle between 8 and 18.