Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
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You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Answer:
3m and 9m
Step-by-step explanation:
length of the rectangle = 2w+3
width of rectangle = w
area = L*W
if area = 27m²
then (2w+3)w=27
=2w²+3w-27=0
using factorization w= 3 or -4.5
w=3m
L=9m
Answer:
52
Step-by-step explanation:
The answer is c
hope that helps :)))
Answer:
DELETE i will answer later doe:)
Step-by-step explanation: