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Anastasy [175]
3 years ago
13

Which of the ordered pairs below satisfy the following equation? Check all that apply. y = 7x A. (84, 12) B. (42, 7) C. (12, 84)

D. (84, 14) E. (6, 42) F. (42, 6)
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0
So you have many ordered pairs here that look like (x , y) So you take each one, for example (84,12) and plug it into that equation you have <span>y=7x</span> (84 , 12) means (x = 84, y = 12 ) so we plug those in <span>12=7(84)</span><span> Does that come out true? if it doe...we have a solution..if not...obviously not :)</span>
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A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim
valentinak56 [21]

45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

n \times 0.05 + d \times 0.10 = 9.15

0.05n + 0.10d = 9.15  ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

<h3>d = 45</h3>

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

<h3>n = 93</h3>

Thus 45 dimes and 93 nickels were in bank

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Answer:

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Step-by-step explanation:

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