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Alex73 [517]
3 years ago
6

Please help!! Will mark you as the Brainliest!!

Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0
The first leg of the graph represents Manuel riding his bike for 3 units of time going 5 units distance gradually increasing his speed.  The second line segment represents Manuel staying where he his for 4 1/2 units of time.  The third represents Manuel going a fast speed back to where he started.  I think.

Or the first is him going that distance picking up speed, the second him going a constant speed, and the third him slowing down/speeding up.
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The table shows the volume V (in cubic feet) of a cube with a side length of x feet. Does the table represent a linear or nonlin
Reika [66]

Answer:

Step-by-step explanation:Determine whether each table represents a linear or nonlinear function. ... Show. YOUY work. Nonlinear; as x increases by 1, y increases by a greater amount of ... A cube has a side length of s meters. ... (Example 4) Nonlinear; sample answer: If you graph the function, the ordered pairs (side length, volume) do not lie on a.

8 0
3 years ago
A tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of each tread type are dri
Minchanka [31]

Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).

We are given the <u>standard deviation for the samples</u>, hence, the t-distribution is used to solve this question.

The standard errors are given by:

s_A = \frac{1.79}{\sqrt{18}} = 0.4219

s_B = \frac{1.95}{\sqrt{18}} = 0.4596

For the distribution of differences, the <u>mean and the standard error</u> are given by:

\overline{x} = \mu_A - \mu_B = 23.95 - 22.19 = 1.76

s = \sqrt{0.4219^2 + 0.4596^2} = 0.6239

The interval is given by:

\overline{x} \pm ts

The critical value for a <u>two-tailed 99% confidence interval</u> with 18 + 18 - 2 = <u>34 df</u> is t = 2.7284.

Then:

\overline{x} - ts = 1.76 - 2.7284(0.6239) = 0.058

\overline{x} + ts = 1.76 + 2.7284(0.6239) = 3.462

The 99% confidence interval for the difference is (0.058, 3.462).

For more on the t-distribution, you can check brainly.com/question/16162795

3 0
3 years ago
I NEED HELP WITH THIS I DONT UNDERSTAND IT
nadezda [96]
16.935 I got a question on a test hope this helps):
8 0
3 years ago
If the scores per round of golfers on the PGA tour are approximately normally distributed with mean 69.3 and standard deviation
shusha [124]

Answer:

0.6069

Step-by-step explanation:

Given an approximately normal distribution:

Z = (x - mean) / standard deviation

Mean = 69.3 ; Standard deviation = 2.58

For :

P(x < 70)

Z = (70 - 69.3) / 2.58

Z = 0.7 / 2.58

Z = 0.2713

P(Z < 0.2713) = 0.6069

8 0
3 years ago
Pls can someone help me‼️‼️‼️‼️<br> and I don’t want files.
ANEK [815]

Answer:

135

Step-by-step explanation:

a line always has a degree of 180 so u just subtract 45 from 180 and get 135

5 0
3 years ago
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