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Gelneren [198K]
3 years ago
5

The mean height of women in a country​ (ages 20-29) is 64.3 inches. A random sample of 75 women in this age group is selected. W

hat is the probability that the mean height for the sample is greater than 65 ​inches? Assume sigma=2.81.
Mathematics
1 answer:
siniylev [52]3 years ago
3 0

Answer:

z(65) = (65-64.2)/[2.81/sqrt(60)] = 0.8/(0.3279)

Step-by-step explanation:

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Find the slope of the line between (1,4) and ( 3 , 10 )
vivado [14]

Answer:

3

Step-by-step explanation:

slope of line = gradient of line

= \frac{10-4}{3-1}

= 3

3 0
2 years ago
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Write the quadratic equation whose roots are 4 and 5, and whose leading coefficient is 4.
Umnica [9.8K]

Answer:

<u>Answer</u><u>:</u><u> </u><u>4</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>0</u><u> </u>

Step-by-step explanation:

• General quadratic equation:

{ \rm{ {x}^{2}  - (sum \: of \: roots)x + (product \: of \: roots) }}

• sum of roots → 4 + 5 = 9

• product of roots → 4 × 5 = 20

• substitute:

{ \boxed{ \rm{4 {x}^{2}  - 9x + 20 }}}

3 0
2 years ago
What is the midpoint of a segment (-2,-7) and (7,4)
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5 0
3 years ago
Help! please give steps :) thanks 20pts
luda_lava [24]
Hello,
26.
period=4
max=3
min=-3

27:
p=8
max=5
min=0

28:
p=8
max= 4 (twice)
min=-4 (twice)


8 0
3 years ago
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The median of a set of consecutive odd integers is 138. If the greatest integer in the set is 145, what is the least integer in
garri49 [273]

Answer:

131

Step-by-step explanation:

Given that:

Median of a consecutive odd integers = 138

Greatest integer In dataset = 145

Least integer in dataset =

Since the integers are consecutive ;

Number of integers to greatest integer value : Greatest integer - median value = 145 - 138 = 7

Hence, 7 integers before the median value should give us the least integer value ;

138 - 7 = 131

CHECK:

131,132,133,134,135,136,137,138,139,140,141,142,143,144,145

Median = (n+1)/2 th term

Median = (15+1)/2 = 8th term = 138

Highest = 145

Least = 131

7 0
3 years ago
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