Assume that adults have IQ scores that are normally distributed with a mean of 94 and a standard deviation of 14. Find the proba
bility that a randomly selected adult has an IQ greater than 107.1. (Hint: Draw a graph.) To help visualize the area of interest, draw a standard normal curve. Label the given values for x and mu . x 94107.1
1 answer:
Answer:
0.6517
Step-by-step explanation:
z = (x - μ)/σ
Z= standard score
x= observed value
μ= mean of the sample
σ= standard deviation of the sample
z = (x - μ)/σ = (107.1 - 94 )/ 14 = 0.9357
probability that a randomly selected adult has an IQ greater than 107.1. = P(Z > 0.935) = 0.6517
NB: the value is 0.6517 is pulled from the z table which can be found at the back of most math text.
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