Answer: 949.85 in 3
Step-by-step explanation:i took the test lol
Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
Answer:
x=6 y=-9
Step-by-step explanation:
- Layer the equations on each other as you would in a subtraction problem:
8x + 2y=30
7x + 2y=24
- Subtract the equation just like you would normally. This should leave 1x=6 or x=6.
- Now that you have your x value, plug it in as x for one of the equations. For the 2nd equation, this leaves:
42+2y=24 then
2y=-18 then
y=-9
- Double check your y value by plugging x=6 into the first equation. This should also leave y=-9.
The answer is (6,-4). By the way, this was very hard to read.
