Solve for u. 8u-21 = 2u-9
2 answers:
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9514 1404 393
Answer:
- ∠QSR = 78°
- ∠SQR = 51°
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
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Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
Ans:
(x+5)(x+1)+8
Step by step explanation:
-5 was mentioned as the 0 of the first root: (x+5). Then with some maneuvering we can plot (-3,4) then add (x+1) because they land on the same y axis. then we add 8 to get it right on the vertex.
Answer:
<em><u>y = d + a · cos(bx - c) ⇒ y = -4cos(4/3x)</u></em>
- a = -4
- b = 4/3
- c = 0
- d = 0
Amplitude = |a| = |-4| = 4
Period =