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VLD [36.1K]
3 years ago
10

Steak cost $3.85 per pound if you buy a 3 pound steak and pay for it with a $20 bill how much change will you get ?

Mathematics
2 answers:
liberstina [14]3 years ago
7 0
8.45 is the answer. :)
Pie3 years ago
3 0

Answer:

$ 8.45

Step-by-step explanation:

3.85 * 3 = 11.55

20 - 11.55 = 8.45

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a frame for mrs. nunez's class picture has an area of 93.5 square inches. the length of the frame measures 8 1/2 inches. what mu
kakasveta [241]

Answer:

Step-by-step explanation:

length times width = area

so you have 8.5w=93.5

divide 8.5 on both sides to get your answer

w= 11

so your width must be 11 inches

7 0
3 years ago
Need the answer thank you!
ohaa [14]

Answer:

256.

Step-by-step explanation:

1 × 4 = 4

4 × 4 = 16

16 × 4 = 64

64 × 4 = 256

4 0
3 years ago
Read 2 more answers
In quadratic drag problem, the deceleration is proportional to the square of velocity
Mars2501 [29]
Part A

Given that a= \frac{dv}{dt} =-kv^2

Then, 

\int dv= -kv^2\int dt \\  \\ \Rightarrow v(t)=-kv^2t+c

For v(0)=v_0, then

v(0)=-kv^2(0)+c=v_0 \\  \\ \Rightarrow c=v_0

Thus, v(t)=-kv(t)^2t+v_0

For v(t)= \frac{1}{2} v_0, we have

\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\  \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\  \\ \Rightarrow kv_0t=2 \\  \\ \Rightarrow t= \frac{2}{kv_0}


Part B

Recall that from part A, 

v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\  \\ \Rightarrow dx=-kv^2tdt+v_0dt \\  \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\  \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a

Now, at initial position, t = 0 and v=v_0, thus we have

x=a

and when the velocity drops to half its value, v= \frac{1}{2} v_0 and t= \frac{2}{kv_0}

Thus,

x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\  \\ =- \frac{1}{2k} + \frac{2}{k} +a

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

- \frac{1}{2k} + \frac{2}{k} +a-a \\  \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}
7 0
3 years ago
Daniella prepares a 1 mg/ml 1 mg/ml myoglobin solution. The molecular weight of myoglobin is 17.8 kDa. 17.8 kDa. Given that the
Marina CMI [18]

Answer:

A = 0.84

Step-by-step explanation:

The absorbance of the myoglobin solution can be calculated by using the Beer-Lambert law:

A = \epsilon*C*l

<u>Where:</u>

<em>A: is the absorbance </em>

<em>ε: is the molar attenuation coefficient = 15,000 M⁻¹cm⁻¹ </em>

<em>l: is the  optical path length = 1 cm</em>

<em>C: is the concentration = 1 mg/ml  </em>

Since the concentration is given in mg/ml and the molar attenuation coefficient is given in M (mol/L) we need to convert the concentration in mg/ml to mol/L and for that, we need to use the molecular weight of myoglobin = 17.8 kDa = 17.8x10³ g/mol:    

C = 1 \frac{mg}{ml} \cdot \frac{1 g}{1000 mg} \cdot \frac{1000 ml}{1 L} \cdot \frac{1 mol}{17.8\cdot 10^{3} g} = 5.62 \cdot 10^{-5} mol/L

Now, we can calculate the absorbance of the myoglobin:

A = 15,000 L*mol^{-1}*cm^{-1}*5.62\cdot 10^{-5} mol*L^{-1}*1 cm = 0.84

Therefore, the absorbance of the myoglobin solution is 0.84.

I hope it helps you!  

8 0
3 years ago
What is Pythagorean theorem
ioda
A^2+B^2=C^2, this formula is used to find the length of a hypotenuse only if the triangle is a right triangle (has a 90 degree angle)
8 0
3 years ago
Read 2 more answers
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