All categories

3 years ago

Steak cost $3.85 per pound if you buy a 3 pound steak and pay for it with a $20 bill how much change will you get ?

Mathematics

2 answers:

liberstina [14]3 years ago

7 0

8.45 is the answer. :)

Pie3 years ago

3 0

Answer:

$ 8.45

Step-by-step explanation:

3.85 * 3 = 11.55

20 - 11.55 = 8.45

You might be interested in

a frame for mrs. nunez's class picture has an area of 93.5 square inches. the length of the frame measures 8 1/2 inches. what mu

kakasveta [241]

Answer:

Step-by-step explanation:

length times width = area

so you have 8.5w=93.5

divide 8.5 on both sides to get your answer

w= 11

so your width must be 11 inches

7 0

3 years ago

Need the answer thank you!

ohaa [14]

Answer:

256.

Step-by-step explanation:

1 × 4 = 4

4 × 4 = 16

16 × 4 = 64

64 × 4 = 256

4 0

3 years ago

Read 2 more answers

In quadratic drag problem, the deceleration is proportional to the square of velocity

Mars2501 [29]

Part A

Given that $a= \frac{dv}{dt} =-kv^2$

Then,

$\int dv= -kv^2\int dt \\ \\ \Rightarrow v(t)=-kv^2t+c$

For $v(0)=v_0$ , then

$v(0)=-kv^2(0)+c=v_0 \\ \\ \Rightarrow c=v_0$

Thus, $v(t)=-kv(t)^2t+v_0$

For $v(t)= \frac{1}{2} v_0$ , we have

$\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\ \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\ \\ \Rightarrow kv_0t=2 \\ \\ \Rightarrow t= \frac{2}{kv_0}$

Part B

Recall that from part A,

$v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\ \\ \Rightarrow dx=-kv^2tdt+v_0dt \\ \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\ \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a$

Now, at initial position, t = 0 and $v=v_0$ , thus we have

$x=a$

and when the velocity drops to half its value, $v= \frac{1}{2} v_0$ and $t= \frac{2}{kv_0}$

Thus,

$x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\ \\ =- \frac{1}{2k} + \frac{2}{k} +a$

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

$- \frac{1}{2k} + \frac{2}{k} +a-a \\ \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}$

7 0

3 years ago

Daniella prepares a 1 mg/ml 1 mg/ml myoglobin solution. The molecular weight of myoglobin is 17.8 kDa. 17.8 kDa. Given that the

Marina CMI [18]

Answer:

A = 0.84

Step-by-step explanation:

The absorbance of the myoglobin solution can be calculated by using the Beer-Lambert law:

$A = \epsilon*C*l$

Where:

A: is the absorbance

ε: is the molar attenuation coefficient = 15,000 M⁻¹cm⁻¹

l: is the optical path length = 1 cm

C: is the concentration = 1 mg/ml

Since the concentration is given in mg/ml and the molar attenuation coefficient is given in M (mol/L) we need to convert the concentration in mg/ml to mol/L and for that, we need to use the molecular weight of myoglobin = 17.8 kDa = 17.8x10³ g/mol:

$C = 1 \frac{mg}{ml} \cdot \frac{1 g}{1000 mg} \cdot \frac{1000 ml}{1 L} \cdot \frac{1 mol}{17.8\cdot 10^{3} g} = 5.62 \cdot 10^{-5} mol/L$