An election ballot asks voters to select four city commissioners from a group of eight candidates. In how many ways can this be
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The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find
Using normal distribution,
Thus
So
Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then
This implies
Thus the babies who are born on or before 238 days are considered to be premature.
Given:
Cory made 21 of the 60 baskets she attempted.
Krista made 16 out of 40 baskets she attempted.
Paul made 17 of the 50 baskets she attempted.
Sally 11 of the 55 she attempted.
To find:
Who had the greatest percentages of baskets made?
Solution:
We know that,
Using this formula, we get
From the above percentages 40% is maximum.
Therefore, Krista has greatest percentage of baskets made.