Subtract the constant vector that is on the left. The arithmetic applies to corresponding elements of the vectors.
![A=\left[\begin{array}{cccc}0&1&-2&3\end{array}\right] -\left[\begin{array}{cccc}11&17&-8&13\end{array}\right]\\\\A=\left[\begin{array}{cccc}-11&-16&6&-10\end{array}\right]\\\\a_{11}=-11\\a_{12}=-16\\a_{13}=6\\a_{14}=-10](https://tex.z-dn.net/?f=%20A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%261%26-2%263%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D11%2617%26-8%2613%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-11%26-16%266%26-10%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5Ca_%7B11%7D%3D-11%5C%5Ca_%7B12%7D%3D-16%5C%5Ca_%7B13%7D%3D6%5C%5Ca_%7B14%7D%3D-10%20)
All of these answers are right
Answer:
x² - 2x + 3
Step-by-step explanation:
y = (x - 1)² + 2
= (x - 1)² + 2 [a - b]² = <em><u>a²- 2ab + b²</u></em>
= x²- 2x + 1 + 2
= x² - 2x + 3
Thus, the standard form of the equation is x² - 2x + 3
Answer:
10x + 10y +10
Step-by-step explanation:
You just multiply 5 with the coefficients.