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Luba_88 [7]
3 years ago
8

Which represents the empirical formula for a3B9

Chemistry
1 answer:
Viktor [21]3 years ago
3 0
A3B9 represents a molecular formula. The representation of the empirical formula for this compound is AB3. This is so because the empirical formula is the simplest ratio of the atoms present in the molecule. You get AB3 when you divide the subscripts of A3B9, this is 3 and 9, by the greatest common factor, which is 3. 3/3 = 1 and 9/3 = 3, so the subscripts for the empirical formula are 1 and 3, which is what AB3 represents. <span>Answer: AB3.</span>
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What is the necessary voltage to power the electrolysis of molten sodium chloride?
sammy [17]

4V  is the necessary voltage to power the electrolysis of molten sodium chloride.

To create sodium metal and chlorine gas, molten (liquid) sodium chloride can be electrolyzed. A Down's cell is the name of the electrolytic cell utilised in the procedure. The liquid sodium ions in a Down's cell are converted to liquid sodium metal at the cathode. Liquid chlorine ions are oxidised to chlorine gas at the anode. Below is an illustration of the reactions and cell potentials:

oxidation: 2Cl^{-} (l) → Cl_{2} (g) + 2e^{-}                                  E°= -1.36V

reduction: Na^{+} (l) + e^{-} → Na (l)                                    E°= -2.71V

overall : 2Na^{+} (l) + 2Cl^{-} (l) → 2Na(l) +Cl_{2} (g)              E°_{cell} = -4.07V

For this electrolysis to take place, the battery needs to supply more than 4 volts. The only means to obtain pure sodium metal is by this reaction, which also serves as a significant source of chlorine gas generation. Swimming pools and other surfaces are frequently cleaned and disinfected with chlorine gas.

Learn more about sodium chloride here;

brainly.com/question/9811771

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6 0
2 years ago
URGENT !! A substance has 55.80% carbon, 7.04% Hydrogen, and 37.16% Oxygen. What is it's empirical and molecular formula if it h
Ede4ka [16]
<h3><u>Answer;</u></h3>

Empirical formula = C₂H₃O

Molecular formula = C₁₄H₂₁O₇

<h3><u>Explanation</u>;</h3>

Empirical formula

Moles of;

Carbon = 55.8 /12 = 4.65 moles

Hydrogen = 7.04/ 1 = 7.04 moles

Oxygen  = 37.16/ 16 = 2.3225 moles

We then get the mole ratio;

4.65/2.3225 = 2.0

7.04/2.3225 = 3.0

2.3225/2.3225 = 1.0

Therefore;

The empirical formula = <u>C₂H₃O</u>

Molecular formula;

(C2H3O)n = 301.35 g

(12 ×2 + 3× 1 + 16×1)n = 301.35

43n = 301.35

  n = 7

Therefore;

Molecular formula = (C2H3O)7

                             <u> = C₁₄H₂₁O₇</u>

6 0
3 years ago
Why do certain Snurfles not survive?
Lelu [443]
Some are weaker than others it’s natural causes or they fight then d1e
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2 years ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
shutvik [7]

Answer:

  • <u>79%</u>

Explanation:

<u>1) Balanced chemical equation:</u>

  • 2S + 3O₂ → 2SO₃

<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

  • Number of moles of O₂

        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

        Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859

        Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5

Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.

<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

  • 0.1875 mol O₂ / x = 3 mol O₂ / 2 mol SO₃

  • x = 0.1875 × 2 / 3 mol SO₃ =  0.125 mol SO₃

<u>5) Yield in grams:</u>

  • mass = number of moles × molar mass = 0.125 mol × 80.06 g/mol =  10.0 g

<u>6) </u><em><u>Percent yield:</u></em>

  • Percent yield, % = (actual yield / theoretical yield) × 100
  • % = (7.9 g / 10.0 g) × 100 = 79%
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1 -Is Apple Juice with No Pulp a pure substance or a mixture ?
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1. Pure substance

2.mixture

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3 years ago
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