The output density is given as kg/m 3, lb/ft 3, lb/gal(US liq) and sl/ft 3. Specific weight is given as N/m 3 and lb f / ft 3.
Yes because they atom with a stable octet electrons is less reactive it does not need any more electrons while an atom that has an partially filled electrons need more electrons to complete octet structure
Molar mass of A l 2 (S O 4 ) 3 = 342.15 g/mol
7.2g/ 342.15 g/mol
you can get number of moles.
then multiply that by12
I see you have access to the internet. Google 'Kelvin to C', and input 251. You'll get -22.15.
Answer:
a. wt% A / Atomic Mass A / (wt% A / Atomic Mass A + wt% B / Atomic Mass B).
b. 11.74%
Explanation:
a. Weight percent is the mass of an element in 100g of the alloy. Atomic percent could be taken as the ratio between moles of an element and the total moles of the alloy.
Assuming a basis of 100g, the moles of A and B (The two elements in the alloy), are:
<em>Moles A:</em>
wt% A / Atomic Mass A
<em>Moles B:</em>
wt% B / Atomic Mass B
<em />
And atomic percent of A is:
<h3>wt% A / Atomic Mass A / (wt% A / Atomic Mass A + wt% B / Atomic Mass B)</h3><h3 />
b. Atomic fraction of Cu in the alloy is (Molar mass Cu: 63.55g/mol; Molar mass Ag: 107.87g/mol):
7.25wt% / 63.55g/mol / (7.25wt% / 63.55g/mol + 92.5wt% / 107.87g/mol)
Atomic fraction Cu = 0.1174 = 11.74%
