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Korvikt [17]
3 years ago
9

When sediment is eroded and then deposited at the mouth of a river, it can form a

Chemistry
1 answer:
wariber [46]3 years ago
7 0

Answer:

fossil?..................

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3 years ago
36.4 g of SnCl2 is dissolved in 135.7 mL of water.
Yuki888 [10]

Answers:

1st: 189.6 g/mol

2nd: 0.1357 L

3rd: 1.41 M

Explanation:

Finding Molar Mass:

SnCl2 = <u>Tin(II) Chloride</u>

Tin has a molar mass of <u>118.71 g/mol</u>

Chloride has a molar mass of <u>35.453 g/mol</u>

Chloride*2 = <u>70.906</u>

<u>118.71 + 70.906 ≈ 189.6 g/mol</u>

Finding Liters of Solution:

L = mL/1000

135.7 mL / 1000 = <u>0.1357</u>

Finding Molarity:

molarity = <u>moles of solute / liters of solution</u>

M = (36.4g /  189.6g) / 0.1357 L = <u>1.41 M</u>

Hope this helped ;)

6 0
2 years ago
A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas i
ElenaW [278]

Answer:

470 °C  

Explanation:

This looks like a case where we can use Charles’ Law:  

\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}

Data:

V₁ = 20 L; T₁ = 100 °C

V₂ = 40 L; T₂ = ?  

Calculations:

(a) Convert the temperature to kelvins

T₁ = (100 + 273.15) K = 373.15 K

(b) Calculate the new temperature

\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}

Note: The answer can have only two significant figures because that is all you gave for the volumes.

(c) Convert the temperature to Celsius

T₂ = (750 – 273.15) °C = 470 °C

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Which conclusion could be made from Ernest Rutherford’s gold foil experiment?
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