All categories

3 years ago

If x/3= x+1/4, What is the value of x

1 answer:

8 0

Well first because in this equation the first value is less than one, we should multiply the whole equation by 3, so
x/3= x+1/4
x=3x+3/4
now we should switch the values
3x+3/4=x
now subtract x from both sides
2x+3/4=0
now subtract 3/4 from both sides
2x=-3/4
now divide both sides by 2
x=3/8
So that's your answer!

You might be interested in

Given a sphere with a radius of 7.5 ft.

ad-work [718]

Answer:

volume of the sphere is V=1766.25 $ft^{3}$

Step-by-step explanation:

step:1

The volume of the sphere formula is V= $\frac{4 pi r^{3} }{n}$

step:2

Given radius of the sphere r=7.5 ft

substitute given radius r=7.5 ft value in volume of the sphere formula

$V=[tex]\frac{4 pi r^{3} }{n}$ \\

V=\frac{4(3.14)(7.5)^{3} }{3}[/tex]

V=1766.25 $ft^{3}$

Final answer is V=1766.25 $ft^{3}$

3 0

3 years ago

A candy store makes strawberry cream chocolates every 8 days and white chocolate truffles every 12 days. The candy store made bo

Elanso [62]

Answer:

on the 24th day they both will make chocolate the LCM of 8 and 12 is 24

4 0

3 years ago

Read 2 more answers

Is 25/99 a terminating decimal or a repeating decimal

BartSMP [9]

Repeating; it's .252525252525252525252525

3 0

3 years ago

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago

Stan drove for h hours at a constant rate of r miles per hour. How many miles did he cover during the final 20 minutes of his dr

valentinak56 [21]

r multiplied by 1/5h

6 0

3 years ago

Read 2 more answers