Answer: 1.) √121= 11
Step-by-step explanation:
11•11=121
A it’s a I think ok because I’m new
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
The answer is d because it 0 has more than one outcome and 0 needs to only have one outcome for it to be a function
1/3, 1/8, 1/24
I'm pretty sure
