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AlladinOne [14]
3 years ago
10

The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds

of thousands of dollars and t is the number of years of operation. he realizes his company is on the down turn and wishes to sell before he ends up in debt. In what year of operation does Mr. Cash’s business show maximum profit? What is the maximum profit? What time will it be too late to sell business?

Mathematics
1 answer:
eduard3 years ago
4 0
We have that

<span>p(t)=-3t^2+18t-4

using a graphing tool, we can see the maximum of the graph
(see the attached figure)

A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?

</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)

<span>B) What is the maximum profit? 

23 (hundred of thousand of dollars) = 2.300.000 dollars

</span>c) What time will it be two late?
 
(This is the time when the graph crosses zero and the profits turn into losses )

5.77 years, or an estimate of about  69 months.

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1 year ago
What is the volume of the composite figure? (Round to the nearest hundredth. Use 3.14 for x.)
marshall27 [118]

The volume of the composite figure is the third option 385.17 cubic centimeters.

Step-by-step explanation:

Step 1:

The composite figure consists of a cone and a half-sphere on top.

We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying \frac{1}{3} with π, the square of the radius (r²) and height (h). Here we substitute π as 3.1415.

The radius is 4 cm and the height is 15 cm.

The volume of the cone :

V = \frac{1}{3} \pi r^{2} h = \frac{1}{3} (3.1415)(4^{2} )(15) = 251.32 cubic cm.

Step 3:

The area of a half-sphere is half of a full sphere.

The volume of a sphere is given by multiplying \frac{4}{3} with π and the cube of the radius (r³).

Here the radius is 4 cm. We take π as 3.1415.

The volume of a full sphere \frac{4}{3} \pi r^{3} = \frac{4}{3} (3.1415) (4^{3}) = 268.07 cubic cm.

The volume of the half-sphere =\frac{1}{2} (268.07) = 134.037 cubic cm.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume 251.32+134.037 = 385.357 cub cm. This is closest to the third option 385.17 cubic centimeters.

5 0
3 years ago
Statistics help please!!!
Andre45 [30]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
1. Find the volume of a cone with a diameter of 14 cm and a height of 25 cm.
slega [8]

Answer:

V≈1282.82

Step-by-step explanation:

V=πr^2h

3=π·72·25

3≈1282.817

8 0
2 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
2 years ago
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