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3 years ago

I don't understand that question, please help Thank u

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

4 0

Answer:

.I didn't understand it either sorry

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The perimeter of a quarter circle is 14.28 KM. What is the quarter circle's radius?

lawyer [7]

Circumference= 2πr
Circumference= perimeter

14.28km= 2(3.14)r
14.28= 6.2831853072r
divide both sides by 6.2831853072
2.27= r

ANSWER: The radius is 2.27km

Hope this helps! :)

3 0

3 years ago

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4?

tiny-mole [99]

For this case we have that by definition, the Greatest Common Factor (GCF) is the largest factor that 2 numbers have in common.

So, we have the following expressions:

$42a ^ 5b ^ 3\\35a ^ 3b ^ 4\\42ab ^ 4$

We look for the positive integers that divide to 35 and 42 without leaving residue:

42: 1,2,3,6,7,14,21

35: 1,5,7

Thus, the GCF of 42 and 35 is 7

Then, the GCF of the three expressions is:

$7ab ^ 3$

Answer:

$7ab ^ 3$

4 0

3 years ago

Anya started solving for the volume of the pyramid using the steps below. V = one-third B h B = 12 (12) = 144 feet squared A squ

beks73 [17]

Answer:

Step-by-step explanation:

V=1/3(144)(15)

hope this helps! :3

3 0

3 years ago

Read 2 more answers

A lighthouse is located on a small island 2 km away from the nearest point P on a straight shoreline and its light makes four re

ddd [48]

Answer:

62.8 km per min

Step-by-step explanation:

Let the diagram of this situation is shown below,

In which $\theta$ is the angle made by light to the straight line joining the lighthouse and P,

∵ Light makes 4 revolutions per minute.

Also, 1 revolution = $2\pi$ radians

So, the change in angle with respect to t ( time ),

$\frac{d\theta}{dt}=8\pi\text{ radians per min}$

Let x be the distance of beam from P,

$\implies \tan \theta = \frac{x}{2}$

Differentiating with respect to x,

$\sec^2 \theta \frac{d\theta}{dt}=\frac{1}{2}\frac{dx}{dt}$

$(1+\tan^2 \theta) (8\pi) = \frac{1}{2}\frac{dx}{dt}$

$(1+\frac{x^2}{2^2})(8\pi) = \frac{1}{2}\frac{dx}{dt}$

If x = 1 km,

$(1+\frac{1}{4})8\pi =\frac{1}{2}\frac{dx}{dt}$

$\frac{5}{4}8\pi = \frac{1}{2}\frac{dx}{dt}$

$\implies \frac{dx}{dt}=\frac{80\pi}{4}= 20\pi\approx 62.8\text{ km per min}$

Hence, the beam of light moving along the shoreline with the speed of 62.8 km per min

7 0

4 years ago

Answer choices: <br> a. 66<br> b. 53 <br> c. 87<br> d. 73

Fofino [41]

Answer is D:73

Explanation:180-124=66
66+37=103
180-103=73

4 0

3 years ago

I don't understand that question, please help Thank u ​

I don't understand that question, please help Thank u