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4 years ago

10

Help??!!? please explain?

1 answer:

Ivahew [28]4 years ago

8 0

Answer:

So, what you want to do first is add the height together.

5+5+5+5= 5*4=20

Then use the formula for finding the surface area of a rectangular prism.

A = 2wl + 2lh + 2hw, where w is the width, the l is the length, and the h is the height.

In other words A= 2(12*10) + 2(10*20) + 2(20*12)

Simplify from there.

A= 2(120) + 2(200) + 2(240)

A= 240 + 400 + 480

A= 1,220

*If this is PLATO, Don't use the comma. It will be marked wrong.*

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diamong [38]

Perpendicular bisector will find you the midpoint

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3 years ago

The function f(x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2,–1)} Which equation is true? f of ne

Rudik [331]

Answer:

f(0)=6

Step-by-step explanation:

When representing function's values by set of ordered pairs, the first one correspond to the x value and the second to the image or "y" value.

When you read f(0) means "when x is 0" then the 6 is the value of the function or the image.

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3 years ago

Read 2 more answers

Pls help if u only know the correct answer!! Thanks!! :))

Inessa05 [86]

Answer:

3.5, 4.2

Step-by-step explanation:

reflect make it not negative and its on y axis so y not affected

7 0

3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

4 years ago

There is a rectangular Prism with a Length of 12, a Width of 20, and a Height of 16. Someone says the Surface Area is 3,840. Are

SOVA2 [1]

Answer:

INCORRECT

Step-by-step explanation:

Given a rectangular prism,

Total Surface Area = 2(LW+LH+WH)

If Length = 12, Width =20, and; Height = 16.

Total Surface Area = 2(12*20+12*16+20*16)

=2(240+192+320)

=2(752)

=1504

The Surface Area is 1504 Square Units, therefore if someone says the surface Area is 3,840, they are incorrect!

7 0

3 years ago