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3 years ago

10

Ben and phoebe are finding the slope of a line. Ben chose two points on the line and used them to find the slope. Phoebe used tw

o different points to find the slope. Did they get the same answer?

1 answer:

timofeeve [1]3 years ago

7 0

Yes because they went the same way but I may not be right so might want to check it

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Which equation is a point slope form equation for line AB ?

kap26 [50]

Answer:

$y-5=\frac{3}{4}(x-6)$

Step-by-step explanation:

we know that

The equation of a line in point slope form is equal to

$y-y1=m(x-x1)$

step 1

Find the slope m

we have the points

A(-2,-1),B(6,5)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{5+1}{6+2}$

$m=\frac{6}{8}$

simplify

$m=\frac{3}{4}$

step 2

Find the equation of the line

we have

$(x1,y1)=(6,5)$

$m=\frac{3}{4}$

substitute

$y-y1=m(x-x1)$

$y-5=\frac{3}{4}(x-6)$

3 0

3 years ago

Can anyone help me please i dont understand this

Katena32 [7]

Answer:

try doing this for each quesion

so you see the negative? well negative means less than more. then use your signs and try to get it done reply if you still dont understand

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I need a word problem that has a negative - positive

AleksandrR [38]

Answer:

Here it is

Step-by-step explanation:

You are 58 dollars in debt, and your friend pays you 73 dollars. How much money do you have? Does that work for you?

8 0

3 years ago

What is the value of 3 in the figure shown below?

NeX [460]

9514 1404 393

Answer:

32

Step-by-step explanation:

Angle E is congruent to angle C, so is the value required to make the sum of angles in triangle ABC be 180°.

∠E = 180° -118° -30° = 32°

The value of x is 32.

7 0

3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

<u>For the first parenthesis:</u>

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

<u>For the second parenthesis:</u>

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago