So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12
so the perimeter = 2(6) + 2(12) = 36
Answer:
35.6 yd²
Step-by-step explanation:
Area of ∆UVW can be solved if we know the lengths of 2 sides and their included angle.
We are Given just 1 side, UV (w). Use the law of sines to find UW (v).
Thus:
W = 137°
w = 19 yd
V = 180 - (137 + 22) = 21° => sum of triangle
v = ??
Plug in the values and solve for v
Multiply both sides by sin(21)
(approximated)
Find area of ∆UVW:
Area = ½*UV*UW*sin(U)
Area = ½*v*w*sin(U)
= ½*10*19*sin(22)
Area = 35.6 yd² (to nearest tenth)
Answer:
Ans = 2.53m
Step-by-step explanation:
It is a simple law of Cosine, on a right-angle triangle draw the length as 5 and the base as 7 the angle is 15°. Find x.
So x = 5² +7² - 2 (5) (7)cos 15°
Solve this and you get your answer.
Hope this was helpful :)
Answer:
The scale factor is -1/4.
Step-by-step explanation:
What are some problems that can occur when using overrides? Check all that apply.
The style guide may become cluttered.Text with overrides can’t be exported to other documents.Word won’t allow you to use more than 10 styles in a document.<span>Text with the override won’t respond when changes are made to its original style.</span>
