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777dan777 [17]
3 years ago
5

Find the probability of rolling a three first and then a ten when a pair of dice is rolled twice

Mathematics
1 answer:
Oxana [17]3 years ago
3 0

Answer:

1/216

Step-by-step explanation:

When a pair of dice is rolled, there are 36 possible different outcomes.

Of those 36 different outcomes, a sum of 3 is obtained in 2 different ways: 1, 2 and 2, 1.

Of those 36 different outcomes, a sum of 10 is possible in 3 different ways: 6, 4; 5, 5; 4, 6.

p(3 followed by 10) = p(3) * p(10) = 2/36 * 3/36 = 1/18 * 1/12 = 1/216

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When Tomas simplified the expression -2.6 + (-5.4), he got 2.8. what mistake did Tomas likely make?
vladimir2022 [97]

Tomas used incorrectly the rule of signs, the expression should be simplified as follows:

-2.6 + (-5.4)

-2.6 -5.4 = 8

<h3></h3><h3>What mistake did Tomas likely make?</h3>

Here Tomas wants to perform an addition between two numbers:

-2.6 + (-5.4)

And the outcome that Tomas gets is:

-2.6 + (-5.4) = 2.8

Here his mistake seems to bee that he thought the second number was a positive number, and he solved the operation:

-2.6 + 5.4

So, he used wrong the rule of signs.

Remember that the rule of signs says that:

(-)*(+) = (+)*(-) = (-)

Using that, we can rewrite the original expression:

-2.6 + (-5.4)

to:

-2.6 - 5.4

Solving that, we get:

-2.6 - 5.4 = -8

Which is the outcome that Tomas would have gotten if he had used correctly the rule of signs.

If you want to learn more about the rule of signs:

brainly.com/question/13333620

#SPJ1

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Step-by-step explanation:

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