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777dan777 [17]
3 years ago
5

Find the probability of rolling a three first and then a ten when a pair of dice is rolled twice

Mathematics
1 answer:
Oxana [17]3 years ago
3 0

Answer:

1/216

Step-by-step explanation:

When a pair of dice is rolled, there are 36 possible different outcomes.

Of those 36 different outcomes, a sum of 3 is obtained in 2 different ways: 1, 2 and 2, 1.

Of those 36 different outcomes, a sum of 10 is possible in 3 different ways: 6, 4; 5, 5; 4, 6.

p(3 followed by 10) = p(3) * p(10) = 2/36 * 3/36 = 1/18 * 1/12 = 1/216

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y = x^2 + 2x...eqn 1

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subst for y in eqn 1...

=> x^2 +2x = 3x +20

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=> (x-5) (x+4) =0

=> x = 5 or -4

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FinnZ [79.3K]

Answer:

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