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3 years ago

3. If I get a 2/3 on an exit ticket. What is that grade out of 5?*

Mathematics

2 answers:

irga5000 [103]3 years ago

8 0

Answer:

4/5

Step-by-step explanation:

Diano4ka-milaya [45]3 years ago

7 0

2/15 sorry if it’s wrong all I did was just divide both of them

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Please help will give brainliest. Links will be banned

AlexFokin [52]

Answer:

I believe it is C.

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2 years ago

A certain company's main source is a mobile app. The function h models the company's annual profit (in million of dollars) as a

cricket20 [7]

Answer:

At price 3 and 11, the profit will be $0

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

A certain companies main source of income is a mobile app. The companies annual profit (in millions of dollars) as a function of the app’s price (in dollars) is modeled by P(x)=-2(x-3)(x-11) which app prices will result in $0 annual profit?

My answer:

Given:

x is the app price
P(x) is the profit earned

If we want to find out the app price that will result in $0 annual profit? It means we need to set the function:

P(x)=-2(x-3)(x-11) = 0

<=> (x-3)(x-11)= 0

<=> x - 3 = 0 or x - 11=0

<=> x = 3 or x = 11

So at price 3 and 11, the profit will be $0

Hope it will find you well.

5 0

2 years ago

Read 2 more answers

PLEASE ANSWER! DESPERATE, DONT KNOW HOW TO DO IT!

Annette [7]

Answer:

a) x = -7

b) x = -3/2

c) x = -3/2

d) x = 2

e) x = -1

f) x = -2

g) x = 7/3

h) z = -18/5

i) x = 6

Explanation:

The are a couple of rules you should know first.

Negative exponent rule: $a^{-x} = \frac{1}{a^{x}}$

A negative exponent means the same thing as the positive exponent as a denominator under 1.

Exponent to another exponent: $(a^{x})^{n}=a^{xn}$

When raising an exponent to another exponent, you multiply the exponents.

Fraction as a base rule: $(\frac{a}{b})^{x} = \frac{a^{x}}{b^{x}}$

Apply the exponent to the numerator and denominator.

Base 1 rule: $1^{x} = 1$

1 to the power of anything is 1.

Focus on exponents only: $a^{x} = a^{n}\\x = n$

If the bases are the same on both sides of the equation, you can solve for "x" in the exponent by focusing on it only.

Write as an exponent: Rewrite a normal number as an exponent instead. Example: $8=2^{3}$ or $125=5^{3}$

Also, you need to know how to rearrange and simplify formulas to isolate variables (by doing reverse operations in reverse BEDMAS order).

Know how to use the distributive property with brackets, when you multiply each of the terms in the brackets with the term on the outside.

Use each of these rules to solve.

a) $2^{x+4} = \frac{1}{8}$ Write 8 as exponent

$2^{x+4} = \frac{1}{2^{3}}$ Negative exponent rule

$2^{x+4} = 2^{-3}$ Focus on exponents only

$x+4 = -3$ Subtract 4 from each side to isolate

$x = -3-4$

$x = -7$

b) $9^{x}=\frac{1}{27}$ Write 27 as exponent

$9^{x}=\frac{1}{3^{3}}$ Write 9 as exponent

$(3^{2})^{x}=\frac{1}{3^{3}}$ Exponent to another exponent

$3^{2x}=\frac{1}{3^{3}}$ Negative exponent rule

$3^{2x}=3^{-3}$ Focus on exponents only

$2x=-3$ Divide both sides by 2 to isolate

$x=-\frac{3}{2}$

c) $25^{x}=\frac{1}{125}$ Rewrite 125 as exponent

$25^{x}=\frac{1}{5^{3}}$ Rewrite 25 as exponent

$(5^{2})^{x}=\frac{1}{5^{3}}$ Exponent to another exponent

$5^{2x}=\frac{1}{5^{3}}$ Negative exponent rule

$5^{2x}=5^{-3}$ Focus only exponents only

$2x=-3$ Divide both sides by 2 to isolate

$x=-\frac{3}{2}$

d) $7(3^{x})=63$ Divide both sides by 7 to isolate

$3^{x}=63/7$

$3^{x}=9$ Write 9 as exponent

$3^{x}=3^{2}$ Focus on exponents

$x=2$

e) $10^{3x}=0.001$ Write 0.001 as fraction

$10^{3x}=\frac{1}{1000}$ Write 1/1000 as exponent

$10^{3x}=\frac{1}{10^{3}}$ Neg. exponent

$10^{3x}=10^{-3}$ Focus on exponents

$3x=-3$ Divide both sides by -3

$x=-3/3$

$x=-1$

f) $6(\frac{1}{10})^{x}=600$ Divide both sides by 6

$(\frac{1}{10})^{x}=\frac{600}{6}$

$(\frac{1}{10})^{x}=100$ Write 100 as exponent

$(\frac{1}{10})^{x}=10^{2}$ Fraction as base rule

$\frac{1^{x}}{10^{x}}=10^{2}$ Base 1 rule

$\frac{1}{10^{x}}=10^{2}$ Neg. exponent

$10^{-x}=10^{2}$ Focus on exponent

$-x=2$ Divide both sides by -1

$x=-2$

g) $27^{x-3}=(\frac{1}{3})^{2}$ Write 27 as exponent

$(3^{3})^{x-3}=(\frac{1}{3})^{2}$ Exponent to another exponent

$3^{3(x-3)}=(\frac{1}{3})^{2}$ Fraction as base

$3^{3(x-3)}=\frac{1^{2}}{3^{2}}$ Base 1 rule

$3^{3(x-3)}=\frac{1}{3^{2}}$ Neg. exponent

$3^{3(x-3)}=3^{-2}$ Focus

$3(x-3)=-2$ Distribute over brackets

$3x-9=-2$ Add 9 to both sides

$3x=-2+9$

$3x=7$ Div. both sides by 3

$x=\frac{7}{3}$

h) $4^{\frac{2z}{3}} = 8^{z+2}$ Write 4 as exponent

$(2^{2})^{\frac{2z}{3}} = 8^{z+2}$ Exponent to another exponent

$2^{2\frac{2z}{3}} = 8^{z+2}$ Write 8 as exponent

$2^{2\frac{2z}{3}} = (2^{3})^{z+2}$ Exponent to another exponent

$2^{2\frac{2z}{3}} = 2^{3(z+2)}$ Focus

$2\frac{2z}{3} = 3(z+2)$ Multiply whole number with fraction

$\frac{4z}{3} = 3(z+2)$ Distribute

$\frac{4z}{3} = 3z+6$ Multiply both sides by 3

$4z = 3(3z+6)$ Distribute

$4z = 9z+18$ Subtract 9z from both sides

$4z-9z = 18$

$-5z = 18$ Div. both sides by -5

$z = -\frac{18}{5}$

i) $5(2)^{x-1}+3=163$ Subtract 3 on both sides

$5(2)^{x-1}=163-3$

$5(2)^{x-1}=160$ Div. both sides by 5

$(2)^{x-1}=160/5$

$(2)^{x-1}=32$ Write 32 as exponent

$(2)^{x-1}=2^{5}$ Focus

$x-1=5$ Add 1 to both sides

$x=5+1$

$x=6$

5 0

3 years ago

Find the measure of z. A. 80° B. 83 ° C. 70 ° D. 87 °

Digiron [165]

The answer to the question is c. 70°

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3 years ago

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What type of transformation does shape A undergo to form shape B?

Svetradugi [14.3K]

a 90° clockwise rotation

7 0

3 years ago

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