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Katyanochek1 [597]
3 years ago
14

choose the equation of the horizontal line that passes through the point (−5, 1). y = −5 x = 1 y = 1 x = −5

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
Horizontal line passing through (-5, 1) is y = 1
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Which factor does the width of the peak of a normal curve depend on?
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<span>The normal curve is described by a bell curved graph. The bell curved graph of a normal distribution depends on two factors: the mean and the standard deviation. The mean identifies the position of the center and the standard deviation determines the height and width of the bell. Therefore, the factor that the width of the peak of the normal curve depends on is the standard deviation.</span>
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At a computer store, a customer is considering 9 different computers,10 different monitors,8 different printers and 2different s
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Answer:

The number of different computer systems possible is 1440.

Step-by-step explanation:

For each computer, there are 10 options of monitor.

For each monitor, there are 8 printers.

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Determine the number of different computer systems possible.

9*10*8*2 = 1440

The number of different computer systems possible is 1440.

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the length of a rectangle is 8in. more than it’s width. the perimeter of the rectangle is 88in. what are the width and length of
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3 years ago
What is x- and y- intercept of -7x + 2y= 14
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The y-intercept is (0,7) and the x-intercept is (-2,0).
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Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
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Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0
3 years ago
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