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Katyanochek1 [597]
3 years ago
14

choose the equation of the horizontal line that passes through the point (−5, 1). y = −5 x = 1 y = 1 x = −5

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
Horizontal line passing through (-5, 1) is y = 1
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A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A
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Answer:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

\bar X_{1}=6.5 represent the sample mean for Atlanta

\bar X_{2}=6.7 represent the sample mean for Chicago

s_{1}=0.5 represent the sample deviation for Atlanta

s_{2}=0.7 represent the sample standard deviation for Chicago

n_{1}=100 sample size for the group Atlanta

n_{2}=110 sample size for the group Chicago

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis:\mu_{1}=\mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

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3 years ago
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The mean sustained wind velocity, v, can be determined by the equation , where p is the air pressure, in millibars, at the cente
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The mean sustained wind velocity has the equation:

v = 6.3 √(1013 - p)


If we are given with the mean sustained wind velocity of 64 m/s, then we can solve for the air pressure using the equation:

64 = 6.3 √(1013 - p)

64/6.3 = √(1013 - p)

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2 years ago
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85% of 2500m pls calculate this
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Answer:

2,125m

Step-by-step explanation:

85% = 85/100

85/100 = x/2500m

Solve by cross multiplying

85(2500) = 100(x)

212,500 = 100x

Divide by 100 on both sides

x = 2,125m

Hope this helps :)

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Answer:

16 meters.

Step-by-step explanation:

There are two things to keep in mind at this point, the first is that a square has all its sides equal and the second is that the perimeter in this type of figure is the sum of all the sides.

Knowing the above, we can deduce that therefore each side of the square measures 4 meters and the perimeter could be calculated since we know the value of all the sides, we know that a square has four sides:

p = 4 +4 +4 +4

p = 16

that is to say that the perimeter is equal to 16 meters.

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