Answer:
X = 12.04 is the answer!
Step-by-step explanation:
Have a nice day!
Answer:
I HASVE FORGOTTEN
Step-by-step explanation:
Answer with explanation:
Given : Sample mean =![\overline{x}=\text{48.47 pounds}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D%5Ctext%7B48.47%20pounds%7D)
Standard deviation : ![\sigma=\text{ 3.1 pounds.}](https://tex.z-dn.net/?f=%5Csigma%3D%5Ctext%7B%203.1%20pounds.%7D)
Sample size : n = 36
Claim : ![\mu\neq50](https://tex.z-dn.net/?f=%5Cmu%5Cneq50)
∴ ![H_0:\mu=50](https://tex.z-dn.net/?f=H_0%3A%5Cmu%3D50)
![H_1:\mu\neq50](https://tex.z-dn.net/?f=H_1%3A%5Cmu%5Cneq50)
Since the alternative hypothesis is two tail , then the test is two tail test.
By using a z statistic and a 0.05 level of significance. Reject
if z < -1.960 or is z> 1.960.
Then , the test static for population mean is given by :-
![z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B%5Coverline%7Bx%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B48.47-50%7D%7B%5Cdfrac%7B3.1%7D%7B%5Csqrt%7B36%7D%7D%7D%5Capprox-2.96)
We reject
since
. We have statistically significant evidence at
to show that the mean amount of garbage per bin is not different from 50.
Left side is 22.
22 x 10 = 220
(20 - 6) x 12 = 168
6 x 20 = 120
220 + 168 + 120 = 508
Thank you very much.
Answer:
25 have a good day
Step-by-step explanation: